使用xpath获取$ variable值时进行数组到字符串的转换通知 [英] Array to String conversion notice when getting $variable value with xpath
问题描述
我正在尝试使用xpath在以下供稿中获取类型元素的名称属性.
Im trying to get the name atriburte of the type element in the following feed using xpath.
<response request="getHierarchyByMarketType" code="001"
message="success" debug="">
<jonny>
<class id="5" name="Formula 1" maxRepDate="2012-12-19" maxRepTime="15:03:34">
<type id="4558" name="F1 Championship" lastUpdateDate="2012-11-26"
lastUpdateTime="16:17:33">
为此,我正在使用
$market_name = $wh_xml->xpath('/response/jonny/class/type/@name');
然后使用
<h2>
<?= $market_name ?>
</h2>
我认为
,但不是返回我期望的"F1冠军" ,而是得到一个:
in my view, but instead of it returning my expected "F1 Championship" im getting a:
数组到字符串的转换
Array to string conversion
注意,但是我不确定为什么,我认为xpath会将@name
的值作为字符串返回?
notice, but I'm not sure why, I thought xpath would return the value of @name
as a string?
推荐答案
在 simeplexml 中,xpath()
方法始终返回array
.因此,它不会返回字符串,并且您会看到警告,因为您将数组当作字符串来使用(将其输出).在PHP中将数组转换为字符串时,您会得到通知,字符串为"Array" .
In simeplexml the xpath()
method always returns an array
. Because of that, it does not return a string and you see the warning because you used the array as if it were a string (outputting it). When you convert an array to a string in PHP, you will get the notice and the string is "Array".
您发现在PHP手册中记录为xpath()
s方法返回类型的内容: http://php .net/simplexmlelement.xpath 以及有关字符串的PHP手册(向下滚动/搜索以下内容):
You find that documented as the xpath()
s method return-type in the PHP manual: http://php.net/simplexmlelement.xpath and also in the PHP manual about strings (scroll down/search the following):
数组总是转换为字符串"Array";因此,
echo
和echo $arr['foo']
的构造. [...]
Arrays are always converted to the string "Array"; because of this,
echo
andecho $arr['foo']
. [...]
该规则的唯一例外是,如果您的xpath查询包含错误,则返回值将为FALSE
.
The only exception to that rule is if your xpath query contains an error, then the return value will the FALSE
.
因此,如果您要查找第一个元素,则可以使用 list
语言构造(如果您的xpath查询没有任何语法错误,并且至少返回一个节点):
So if you're looking for the first element, you can use the list
language construct (if your xpath-query does not have any syntax errors and is returning at least one node):
list($market_name) = $wh_xml->xpath('/response/jonny/class/type/@name');
^^^^^^^^^^^^^^^^^^
如果您使用的是PHP 5.4,还可以直接访问第一个数组值:
If you're using PHP 5.4 you can also directly access the first array value:
$market_name = $wh_xml->xpath('/response/jonny/class/type/@name')[0];
^^^
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