注意:数组到字符串的转换 [英] Notice: Array to string conversion in

问题描述

我正在尝试从数据库中选择一个值并使用 SELECT 将其显示给用户.但是我不断收到此错误:

I'm trying to select a value from a database and display it to the user using SELECT. However I keep getting this error:

Notice: Array to string conversion in (pathname) on line 36.

我认为 @mysql_fetch_assoc(); 会解决这个问题，但我仍然收到通知.这是我收到错误的代码部分:

I thought that the @mysql_fetch_assoc(); would fix this but I still get the notice. This is the part of the code where I'm getting the error:

  {
  $loggedin = 1;

  $get = @mysql_query("SELECT money FROM players WHERE username = 
 '$_SESSION[username]'");
  $money = @mysql_fetch_assoc($get);

  echo '<p id= "status">'.$_SESSION['username'].'<br>
  Money: '.$money.'.
  </p>';
  }

我做错了什么?我对 PHP 还很陌生.

What am I doing wrong? I'm pretty new to PHP.

推荐答案

问题在于 $money 是一个数组，而您将其视为字符串或可以轻松转换为字符串的变量.你应该这样说:

The problem is that $money is an array and you are treating it like a string or a variable which can be easily converted to string. You should say something like:

 '.... Money:'.$money['money']

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