如何解决 PHP 错误“注意:数组到字符串的转换..." [英] How to solve PHP error 'Notice: Array to string conversion in...'
问题描述
我有一个 PHP 文件试图回显 $_POST 并且出现错误，代码如下:
I have a PHP file that tries to echo a $_POST and I get an error, here is the code:
echo "<html>";
echo "<body>";
for($i=0; $i<5;$i++){
echo "<input name='C[]' value='$Texting[$i]' " .
"style='background-color:#D0A9F5;'></input>";
}
echo "</body>";
echo "</html>";
echo '<input type="submit" value="Save The Table" name="G"></input>'
这是回显 POST 的代码.
Here is the code to echo the POST.
if(!empty($_POST['G'])){
echo $_POST['C'];
}
但是当代码运行时，我收到如下错误:
But when the code runs I get an error like:
Notice: Array to string conversion in
C:\xampp\htdocs\PHIS\FinalSubmissionOfTheFormPHP.php on line 8
这个错误是什么意思，我该如何解决?
What does this error mean and how do I fix it?
推荐答案
当你有许多名为 C[] 的 HTML 输入时，你在另一端的 POST 数组中得到的是这些的数组$_POST['C'] 中的值.所以当你 echo 时，你正在尝试打印一个数组，所以它所做的只是打印 Array 和一个通知.
When you have many HTML inputs named C[] what you get in the POST array on the other end is an array of these values in $_POST['C']. So when you echo that, you are trying to print an array, so all it does is print Array and a notice.
要正确打印数组，您可以遍历它并echo每个元素，或者您可以使用print_r.
To print properly an array, you either loop through it and echo each element, or you can use print_r.
或者，如果您不知道它是数组还是字符串或其他什么，您可以使用 var_dump($var) 它会告诉您它是什么类型以及它的内容是什么.仅将其用于调试目的.
Alternatively, if you don't know if it's an array or a string or whatever, you can use var_dump($var) which will tell you what type it is and what it's content is. Use that for debugging purposes only.
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