如何解决PHP错误'注意：数组到字符串转换...' [英] How to solve PHP error 'Notice: Array to string conversion in...'
问题描述
我有一个试图回显 $ _ POST 的PHP文件，并且出现错误，下面是代码：
echo< html>;
echo< body>;
for（$ i = 0; $ i <5; $ i ++）{
echo< input name ='C []'value ='$ Texting [$ i]'。
style ='background-color：＃D0A9F5;'>< / input>;
}
echo< / body>;
回显< / html>;
echo'< input type =submitvalue =Save The Tablename =G>< / input>'
这里是回显POST的代码。
if（！empty （$ _POST ['G']））{
echo $ _POST ['C'];
}
但是当代码运行时，我得到一个错误：
注意：数组到字符串转换在
C：\xampp\htdocs\PHIS\FinalSubmissionOfTheFormPHP.php on line 8
这个错误是什么意思，我该如何解决它？
$ _ POST ['C'] >中的数组。所以，当你 echo 时，你正试图打印一个数组，所以它所做的只是打印 Array 和一个通知。 要正确打印一个数组，您可以循环遍历它并为每个元素
echo ，或者您可以使用 print_r 。 另外，如果你不知道它是一个数组还是一个字符串， var_dump（$ var）它会告诉你它是什么类型以及它的内容是什么。仅用于调试目的。
I have a PHP file that tries to echo a $_POST and I get an error, here is the code:
echo "<html>";
echo "<body>";
for($i=0; $i<5;$i++){
echo "<input name='C[]' value='$Texting[$i]' " .
"style='background-color:#D0A9F5;'></input>";
}
echo "</body>";
echo "</html>";
echo '<input type="submit" value="Save The Table" name="G"></input>'
Here is the code to echo the POST.
if(!empty($_POST['G'])){
echo $_POST['C'];
}
But when the code runs I get an error like:
Notice: Array to string conversion in
C:\xampp\htdocs\PHIS\FinalSubmissionOfTheFormPHP.php on line 8
What does this error mean and how do I fix it?
When you have many HTML inputs named C[] what you get in the POST array on the other end is an array of these values in $_POST['C']. So when you echo that, you are trying to print an array, so all it does is print Array and a notice.
To print properly an array, you either loop through it and echo each element, or you can use print_r.
Alternatively, if you don't know if it's an array or a string or whatever, you can use var_dump($var) which will tell you what type it is and what it's content is. Use that for debugging purposes only.
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