PHP array_merge如果不为空 [英] PHP array_merge if not empty

问题描述

尝试合并4个数组，但某些数组在某些时候可能为空.

Trying to merge 4 arrays, but some may be empty at certain times.

$array_1 = array('something1', something2);
$array_2 = array('something3', something4);
$array_3 = array();
$array_4 = array('something1', something2);

$list = array_merge($array_1,$array_2,$array_3,$array_4);

print_r($list);

但是，如果其中一个数组为空，则会出现错误. 我一直在谷歌搜索，但是我找不到关于合并前如何检查空数组的可靠简单答案.

But if one of the arrays are empty, there will be an error. I've been googling forever, but I can't find a solid simple answer on how to check for empty arrays before merging.

参数2不是数组

Argument #2 is not an array

或者任何一个为空的数组都是参数编号.合并前如何去除空数组?

Or whichever array is empty is the argument number. How do I strip out empty arrays before merging?

推荐答案

好的，到这里，这应该可以解决问题(如果您将初始数组作为数组):

Okay here you go, this should do the trick (if you make array of the initial arrays):

$arrs = array();

$arrs[] = array('something1', something2);
$arrs[] = array('something3', something4);
$arrs[] = array();
$arrs[] = array('something1', something2);

$list = array();

foreach($arrs as $arr) {
    if(is_array($arr)) {
        $list = array_merge($list, $arr);
    }
}

print_r($list);

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