array_merge改变键 [英] array_merge changes the keys
本文介绍了array_merge改变键的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我得到了以下数组:
$ ARR =阵列(6 =>'Somedata',7 =>'Somedata1',8 =>'Somedata2');
问题是,当我使用 array_merge((阵列)选择数据,$ ARR);
,它确实改变了数组键为:
阵列
(
[0] =>未标明
[1] => Somedata
[2] => Somedata1
[3] => Somedata2
)
这有可能跳过 array_merge
键preversion所以输出会是什么样子呢?
阵列
(
[0] =>未标明
[6] => Somedata
[7] => Somedata1
[8] => Somedata2
)
解决方案
使用 +
运营商创建2阵列的工会:
$ ARR =阵列(6 =>'Somedata',7 =>'Somedata1',8 =>'Somedata2');$结果=(阵列)'选择数据'+ $改编;后续代码var_dump($结果);
结果:
阵列(4){
[0] =>
串(15)选择数据
[6] =>
串(8)Somedata
[7] =>
串(9)Somedata1
[8] =>
串(9)Somedata2
}
I got the following array:
$arr = array(6 => 'Somedata', 7 => 'Somedata1', 8 => 'Somedata2');
The problem is that, when I use array_merge( (array) "Select the data", $arr);
, it does change the array keys into:
Array
(
[0] => Not specified
[1] => Somedata
[2] => Somedata1
[3] => Somedata2
)
Is that possible to skip the array_merge
key preversion so the output would look like this?
Array
(
[0] => Not specified
[6] => Somedata
[7] => Somedata1
[8] => Somedata2
)
解决方案
Use the +
operator to create a union of the 2 arrays:
$arr = array(6 => 'Somedata', 7 => 'Somedata1', 8 => 'Somedata2');
$result = (array)'Select the data' + $arr;
var_dump($result);
Result:
array(4) {
[0]=>
string(15) "Select the data"
[6]=>
string(8) "Somedata"
[7]=>
string(9) "Somedata1"
[8]=>
string(9) "Somedata2"
}
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