结合javascript/jQuery和PHP [英] Combining javascript / jQuery and PHP

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本文介绍了结合javascript/jQuery和PHP的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用Uploadify上传图片.现在,我需要获取正确的上传路径.

I'm using Uploadify to upload an image. Now I need to get the correct upload path.

我有以下代码/脚本:

  <?php
    $uploadifyPath = get_bloginfo('url') . '/wp-content/plugins/uploadify/';
    $galleryPath = "'".getGalleryURL('1620')."'"; // <--- 1620 is inputed by me. 
  ?>

  <input id="galleryID" type="hidden" value="1620" name="galleryID"/>
  <input id="fileInput" name="fileInput" type="file" />

  <script type="text/javascript">// <![CDATA[
    $(document).ready(function() {
      $('#fileInput').uploadify({
          'uploader'  : '<?php echo $uploadifyPath ?>uploadify.swf',
          'script'    : '<?php echo $uploadifyPath ?>uploadify.php',
          'cancelImg' : '<?php echo $uploadifyPath ?>cancel.png',
          'auto'      : true,
          'folder'    : <?php echo $galleryPath ?>
      });
    });
  // ]]></script>

我如何使用jQuery获取galleryID的值并将其输入到函数getGalleryURL()中?

How can I, with jQuery, get the value of galleryID and input it into my function getGalleryURL() ?

或者...有更好的方法吗?

Or... is there a better way to do this??

推荐答案

通过jQuery进行AJAX调用,以使PHP知道galleryID,然后使用其回调来加载uploadify.

Do an AJAX call via jQuery to let PHP know the galleryID and then use it's callback to load uploadify.

这篇关于结合javascript/jQuery和PHP的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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