$ _REQUEST超级数组未在$ GLOBALS数组中初始化 [英] $_REQUEST superarray not initialized in $GLOBALS array

问题描述

问题

因此，我具有此功能，可以从$ _REQUEST，$ _ POST，$ _ GET或$ _COOKIE数组中检索并继续处理数据.我知道仅从函数调用中使用哪个数组.简化前:

function gg( $name, $type="_REQUEST" ) {
    return isset( $GLOBALS[$type][$name] ) ? $GLOBALS[$type][$name] : false;
}

它非常适合以下呼叫:

gg('var', '_GET');
gg('var2', '_POST');

但由于以下原因而严重失败:

gg('var');
// or
gg('var', '_REQUEST');

我设法将这个问题简化为2行:

print_r( $GLOBALS['_REQUEST'] ); // this line returns nothing...
print_r( $_REQUEST ); // ...UNLESS this line is present anywhere in the code

现在，我的明显问题是:是否有必要初始化$ GLOBALS中存在的$ _REQUEST数组?

其他信息:

php: 5.3.3-7
apache: 2.2.16

also I'm running on CGI/FastCGI

编辑&解决方案

1

此处最简单的解决方案是编辑php.ini并在其中更改 auto_globals_jit 的值从开到关.

auto_globals_jit Off

2

相反，您可以在内部使用 ini_set()您的源文件，但是它对我不起作用...

ini_set("auto_globals_jit", "Off");

3

另一种解决方案是对所有内容使用 $ GLOBALS 数组除了 $ _REQUEST 之外，对于$ _REQUEST请求，直接调用$ _REQUEST数组:D

if($type == "REQUEST") return $_REQUEST[$name];
else return ${"_".$type}[$name]; // or $GLOBALS["_".$type][$name] if previous won't work

解决方案

无法在我的设置中复制它，因此可能是CGI问题?作为解决方法，您可以执行以下操作……

function gg( $name, $type="_REQUEST" ) {
    return isset( ${$type}[$name] ) ? ${$type}[$name] : false;
}

可能会引起关注:

自PHP 5.4起，$ GLOBALS现在已及时初始化.这表示 现在，不使用$ GLOBALS变量是一个优势 避免初始化它的开销. http://www.php.net/manual/en/reserved. variables.globals.php

更新.请参见发布:

使用可变变量时未创建$ _REQUEST吗?

PROBLEM

So, I have this function to retrieve and proceed data from $_REQUEST, $_POST, $_GET or $_COOKIE arrays. I know which array to use only from function call. Simplified ex:

function gg( $name, $type="_REQUEST" ) {
    return isset( $GLOBALS[$type][$name] ) ? $GLOBALS[$type][$name] : false;
}

And it works perfectly for calls like:

gg('var', '_GET');
gg('var2', '_POST');

But fails dramatically for:

gg('var');
// or
gg('var', '_REQUEST');

I managed to simplify this problem thou to 2 lines:

print_r( $GLOBALS['_REQUEST'] ); // this line returns nothing...
print_r( $_REQUEST ); // ...UNLESS this line is present anywhere in the code

Now, my obvious question is: Is there any necessity to initialize this $_REQUEST array to be present in $GLOBALS?

additional info:

php: 5.3.3-7
apache: 2.2.16

also I'm running on CGI/FastCGI

EDIT & SOLUTION

1

As found here the easiest solution would be to edit php.ini and change there value of auto_globals_jit from On to Off.

auto_globals_jit Off

2

Instead of this you can use ini_set() inside of your source file, however it didn't work for me...

ini_set("auto_globals_jit", "Off");

3

Yet another solution is to use $GLOBALS array to everything except $_REQUEST and for $_REQUEST requests call directly to $_REQUEST array :D

if($type == "REQUEST") return $_REQUEST[$name];
else return ${"_".$type}[$name]; // or $GLOBALS["_".$type][$name] if previous won't work

解决方案

Couldn't replicate this on my setup so it could possibly be CGI issue? As a workaround you could do something like this...

function gg( $name, $type="_REQUEST" ) {
    return isset( ${$type}[$name] ) ? ${$type}[$name] : false;
}

Might be of interest:

As of PHP 5.4 $GLOBALS is now initialized just-in-time. This means there now is an advantage to not use the $GLOBALS variable as you can avoid the overhead of initializing it. http://www.php.net/manual/en/reserved.variables.globals.php

Update. See Post:

$_REQUEST not created when using variable variables?

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