用户在Java中的基本阅读输入 [英] basic reading input from user in java

问题描述

我想读取一个字符并将其存储到char[]数组中，这是我的方法，称为getaline

I want to read a character and store it into the char[] array and here is my method called getaline

public static int getaline(char message[], int maxlength)
{
     int index = 0;
     while (message[index] != '\n')
     {
         message[index] = fgetc(System.out);
         index++;
     }
     index++;
}

和我的fgetc方法:

public static int fgetc(InputStream stream)

，此方法应从输入流中返回一个字符.

and this method should returns a character from the input stream.

但是我在编译时总是收到错误消息:

But i keep getting an error message when i compile:

错误:可能会丢失精度

error: possible loss of precision

message[index] = fgetc(System.in);
                       ^
required: char

found:    int

我应该在fgetc里面放些什么，以便我可以从用户那里收集输入信息?

what should i put inside fgetc so that i can collect input from the user??

推荐答案

您的代码期望使用char，但是您在此处返回int:

Your code is expecting a char, but you return an int here:

public static int fgetc(InputStream stream)
//            ↑ tells method will return an int

您可以

• 更改方法签名以返回char.

public static char fgetc(InputStream stream)
//            ↑ tells method will return a char

将值返回到char

投射转换(§5.5)将表达式的类型转换为由强制转换运算符(

Casting conversion (§5.5) converts the type of an expression to a type explicitly specified by a cast operator (§15.16).

message[index] = (char) fgetc(System.in);
//               ↑ cast returning value to a char

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