从十六进制到整数C#，非常大的数字 [英] Hex to int C# with VERY big numbers

问题描述

我有一个256个字符的长字符串，其中包含一个十六进制值:

I have a 256 chars long string that contains a hex value:

EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679

EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679

我想将其转换为具有如下数字的字符串:

I want to convert it to a string with numbers like this:

102721434037452409244947064576168505707480035762262934026941212181473785225928879178124028140134582697986427982801088884553963961786856967476796792433168989860379885762727214550528198941038582937788145880903882393999022181847665735412629158069472569467123076072

102721434037452409244947064576168505707480035762262934026941212181473785225928879178124028140134582697986427982801088884553965371786856967476796072433168989860379885762727214550528198941038582937788145880903882293999022181847665735412629158069472562567144696160522107094738216218810820997773451212693036210879

这么大的数字怎么办?

谢谢.

推荐答案

使用 BigInteger.Parse 将十六进制表示形式解析为BigInteger的实例(使用 NumberStyles.HexNumber ) ，然后 BigInteger.ToString 以获得小数表示.

Use BigInteger. Specifically, you can use BigInteger.Parse to parse the hexadecimal representation to an instance of BigInteger (use NumberStyles.HexNumber), and then BigInteger.ToString to get the decimal representation.

var number = BigInteger.Parse(
    "EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679",
    NumberStyles.HexNumber
);
var s = number.ToString();

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