Zend Framework 2-如何包括库中的部分库 [英] Zend Framework 2 - How to include partial from library

问题描述

我写了一部分，希望在几个模块中使用.我认为最好的方法是将其放入我的自定义库中.

I wrote a partial which I want to use in several modules. I thought the best way would be to put it into my custom library.

但是不幸的是，如果不使用类似以下这样的丑陋路径，我将无法找到一种包括该部分内容的方法:

But unfortunately I couldn't figure out a way to include this partial without using a very ugly path like:

echo $this->partial('/../../../../vendor/myvendor/library/MyVendor/View/Views/FormPartial.phtml'
, array(...));

有什么想法可以从我的角度链接到我的供应商目录吗?

Any ideas how to link to my vendor directory from my view?

推荐答案

问题是解析器无法解析您提供的视图模板的路径.我通常会在module.config.php

The problem is the resolver can't resolve the path of the view template you had provided. I usually add a configuration entry for all accessible partials in the template_map entry in the module.config.php

例如 我的view/layout/header.phtml和view/layout/footer.phtml

for example I have header and footer partials like this my view/layout/header.phtml and view/layout/footer.phtml

下面是我的配置

'template_map' => array(
    'layout/layout'         => __DIR__ . '/../view/layout/layout.phtml',
    'header'                => __DIR__ . '/../view/layout/header.phtml',
    'footer'                => __DIR__ . '/../view/layout/footer.phtml',
    'error/404'             => __DIR__ . '/../view/error/404.phtml',
    'error/index'           => __DIR__ . '/../view/error/index.phtml',
),

在我的布局视图脚本中，我简单地放入了

and inside my layout view script I simply put

<?php echo $this->partial('header'); ?>

和

<?php echo $this->partial('footer'); ?>

如果您的部分代码采用/module/controller/action格式，那么您也可以这样做

Another if you have your partials under /module/controller/action format you can also do

<?php echo $this->partial('/module/controller/action'); ?>

您应将视图脚本放置在模块控制器文件夹的视图文件夹中

you should place the view script in the view folder of your module's controller folder

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