C-如何在数组中存储多个字符串 [英] C - how to store multiple strings in an array

问题描述

想知道如何在数组中存储不同的字符串. 例如，用户输入"qwe"，然后程序会将其存储在数组变量[0]中.输入另一个字符串，然后将其存储为变量[1]，依此类推

Wondering how store different strings in an array. For example a user would input 'qwe' and the program would then store that in an array variable[0]. Entering another string would then store it as variable[1] and so on

int
main(int argc, char *argv[]) {
    char variable[1000];
    int i;

    printf("enter a variable\n");
    scanf("%s", variable);
    for (i = 0; ??? ;i++) {


        printf("The variable entered was: %s\n",variable[i]);
    }
return 0;

我是C语言的新手，所以我不知道我在做什么.但这就是到目前为止我想出的，我想知道我是否可以得到一些帮助来填补其余的内容 谢谢！

Im new to C so I have no idea what im doing. but thats what I have came up with so far and was wondering if I could get some help with filling in the rest Thanks!

推荐答案

您可以使用2D数组存储多个字符串.对于10个长度为100的字符串

You can use 2D array to store multiple strings. For 10 strings each of length 100

char variable[10][100];

printf("Enter Strings\n");
for (int i = 0; i < 10 ;i++)  
    scanf("%100s", variable[i]); 

更好地使用fgets读取字符串.

Better to use fgets to read string.

fgets(variable[i], sizeof(variable[i]), stdin);  

您还可以通过使用指向char的指针数组来使用动态内存分配.

You can also use dynamic memory allocation by using an array of pointers to char.

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