如何在c / c ++中存储大字符串，大小接近10 ^ 6个字符 [英] how to store large strings in c/c++ having size nearly 10^6 characters

问题描述

如何在c / c ++中存储大字符串，大小接近10 ^ 6个字符

how to store large strings in c/c++ having size nearly 10^6 characters

推荐答案

如果你事先知道确切的大小并且它不会改变，只需使用 new 。你应该能够毫无问题地分配一千倍。



如果您事先不知道确切的大小，或者字符串内容（和大小） ）会改变，然后在理论上你应该使用类 std :: string 。如果需要，它将负责（重新）分配。也就是说，如果您创建一组结构合理的较小字符串，那么任何更改都将花费相当多的时间来处理单个大字符串。例如，如果字符串包含文本文件的内容，则将每一行存储在单独的字符串变量中更为明智。

If you know the exact size in advance and it won't change, just use new. You should be able to allocate a thousand times as much without a problem.

If you don't know the exact size in advance, or the string contents (and size) will change, then in theory you should use the class std::string instead. It will take care of (re)allocations, if needed. That said, any change will take considerably more time for a single large string, than it would take if you created a properly structured set of smaller strings instead. If for instance the string holds the contents of a text file, it would be more sensible to store each line inside a separate string variable.

只需使用<$ c $分配足够大小的缓冲区c> new （C ++）或 malloc （C）。

Just allocate buffers with sufficient size using new (C++) or malloc (C).

我会查看标准模板库std :: string





http://www.cprogramming.com/tutorial/string.html [ ^ ]

I would look at the Standard Template Library std::string


http://www.cprogramming.com/tutorial/string.html[^]

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