使用awk，如何将日期转换为星期和季度? [英] Using awk, how to convert dates to week and quarter?

问题描述

使用awk，如何将日期(yyyy-mm-dd)转换为星期和季度(将一周的第一天设置为星期一)?

Using awk, how to convert dates (yyyy-mm-dd) to week and quarter (first day of week set to monday)?

输入:

a;2016-04-25;10
b;2016-07-25;20
c;2016-10-25;30
d;2017-02-25;40

想要的输出:

a;2016-04-25;10;2016-w17;2016-q2
b;2016-07-25;20;2016-w30;2016-q3
c;2016-10-25;30;2016-w43;2016-q4
d;2017-02-25;40;2017-w8;2017-q1

推荐答案

awk 解决方案:

awk solution:

awk -F';' '{ split($2,d,"-"); w = strftime("%W", mktime(d[1]" "d[2]" "d[3]" 00 00 00")); 
           q = int((d[2]+2)/3); 
           print $0,d[1]"-w"w,d[1]"-q"q}' OFS=';' file

输出:

a;2016-04-25;10;2016-w17;2016-q2
b;2016-07-25;20;2016-w30;2016-q3
c;2016-10-25;30;2016-w43;2016-q4
d;2017-02-25;40;2017-w08;2017-q1

---

• split($2,d,"-")-用分隔符-

  ---

  • split($2,d,"-") - split the 2nd field (date) by separator -

    mktime(datespec)-将 datespec (日期规范)转换为时间戳

    mktime(datespec) - turn datespec (date specification) into a timestamp

    strftime("%W", mktime(d[1]" "d[2]" "d[3]" 00 00 00"))-根据%W(一年中的星期几)格式化mktime()函数返回的时间

    strftime("%W", mktime(d[1]" "d[2]" "d[3]" 00 00 00")) - format the time returned by mktime() function according to %W (the week number of the year)

    q = int((d[2]+2)/3)-计算季度号.该季度等于 3 个月.因此，我们将3作为除数.

    q = int((d[2]+2)/3) - calculating the quarter number. The quarter is equivalent to 3 months. So we'll use 3 as a divisor.

    https://www.gnu.org/software/gawk/manual/html_node/Time-Functions.html

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