排序日期从壁橱到现在的第一和过去在底部 [英] Sort dates with closets to now first and past at the bottom

问题描述

我有一个表格视图，其中有多个日期.我需要对日期进行排序，以使降序最大的日期在顶部((indexPath.row == 0))，而过去的日期必须在底部((indexPath.row == ´lastRows´))在其他即将到来的日期之间.

I have a tableview in which there are multiple date. I need to sort the dates so that the most descending date is at the top ((indexPath.row == 0)) and the past dates needs to be at the bottom ((indexPath.row == ´lastRows´)) and in between the other upcoming dates.

我一直在四处寻找找不到合适的解决方案.以下代码仅将最早的日期显示在第一位-未能按照我的期望将过去的日期放在底部. (有关问题的更清晰示例，请参见图片:

I have been looking around without finding a proper solution. The following code only displays the earliest date first - failing to put the past dates at the bottom as I desire. (see picture for clearer example of the problem, the sort I want:

• 即将到来的人
• 即将到来的2

• 过去的日期 )

• Upcoming One
• Upcoming 2

• Past Date )

dqItems.sort(by: {$0.date < $1.date})

有没有办法做到这一点?或者，当日期成为过去时，将日期(及其单元格)推到表格视图的底部吗?

Is there a way of accomplishing this? Alternatively pushing a date (and its cell) to the bottom of the table view when the date becomes the past?

推荐答案

不是使用.sort，而是使用.sorted获取排序后的副本.然后搜索排序后的副本以查找当前时间所在的位置.使用该索引制作几个切片，并将切片复制到所需的位置(返回原始数组).

Rather than use .sort, use .sorted to get a sorted copy. Then search the sorted copy to find where the current time belongs. Use that index to make a couple of slices and copy the slices where you want them (back in the original array).

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