ES6:使用不区分大小写的术语过滤数据 [英] ES6: Filter data with case insensitive term

问题描述

这是我通过标题值过滤某些data的方法:

This is how I filter some data by title value:

data.filter(x => x.title.includes(term))

像这样的数据

Sample one
Sample Two
Bla two

将被简化为"

Bla two

如果我按two进行过滤.

但是我需要得到过滤后的结果

But I need to get the filtered result

Sample Two
Bla two

推荐答案

您可以使用不区分大小写的正则表达式:

You can use a case-insensitive regular expression:

// Note that this assumes that you are certain that `term` contains
// no characters that are treated as special characters by a RegExp.
data.filter(x => new RegExp(term, 'i').test(x.title));

一种可能更简单，更安全的方法是将字符串转换为小写并进行比较:

A perhaps easier and safer approach is to convert the strings to lowercase and compare:

data.filter(x => x.title.toLowerCase().includes(term.toLowerCase()))

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