使用不区分大小写的搜索过滤字典 [英] Filter Dictionary with a case insensitive search

问题描述

这是关于如何过滤词典的后续问题我需要过滤器不区分大小写

This is a follow-up question on How to Filter a Dictionary only I need the filter to be case-insensitive

我有一个字典，用于填充Swift 3中的Pickerview。

I have a dictionary that populates a Pickerview in Swift 3.

var facilityDict:       [Int: [String: String]] = [:]

17：[id：199，facilitycode：036，location_name：Centerpoint
医疗办公室 ]，

41：[id：223，facilitycode：162，
location_name：暗岭医疗中心]，

14：[id：196，
facilitycode：023，location_name：Spinnerpark]，

20：[id：
202，facilitycode：048，location_name：教育剧场，

30：[id：212，facilitycode：090， location_name：合作伙伴
医疗办公室]，

49：[id：231，facilitycode：223，
location_name： GreenBay行政办公室]

17: ["id": "199", "facilitycode": "036", "location_name": "Centerpoint Medical Offices"],
41: ["id": "223", "facilitycode": "162", "location_name": "Dark Ridge Medical Center"],
14: ["id": "196", "facilitycode": "023", "location_name": "Spinnerpark"],
20: ["id": "202", "facilitycode": "048", "location_name": "Educational Theater"],
30: ["id": "212", "facilitycode": "090", "location_name": "Partner Medical Offices"],
49: ["id": "231", "facilitycode": "223", "location_name": "GreenBay Administrative Offices"]

字典很长。我有一个 Textbox 在数据更改时触发，我用它来创建搜索变量。如果有人输入ar，我想过滤字典中包含字符ar的所有内容，以便我可以使用原始大字典列表的小得多的子部分重置Picker列表。

The Dictionary is quite long. I have a Textbox that fires when data is changed and I use this to create a search variable. If someone types in "ar", I want to filter every thing in the dictionary that has the characters "ar" in it so that I can reset the Picker list with a much smaller subsection of the original Big Dictionary list.

过滤器
let filteredDictionaries = facilityDict.filter {$ 0.value.contains（其中：{$ 0.value.contains（ ar。）}）}。map {$ 0.value}
似乎很好地过滤了字典，但是我需要搜索不区分大小写。我可以设置选项以将过滤器显示更改为不区分大小写吗？

The filter let filteredDictionaries = facilityDict.filter{$0.value.contains(where: {$0.value.contains("ar")})}.map{$0.value} seems to filter the dictionary well, However I need the search to be case-insensitive. Are there options I can set to change the filter show to case insensitive?

推荐答案

包含方法与<$ c相同$ c> range（of：String）！= nil 没有任何选项。您只需要使用String！= nil和caseInsensitive选项的范围：

Contains method it is the same as range(of: "String") != nil without any options. All you need is to use range of String != nil with caseInsensitive options:

extension String {
    func contains(_ string: String, options: CompareOptions) -> Bool {
        return range(of: string, options: options) != nil
    }
}

现在你可以这样做：

"whatever".contains("ER", options: .caseInsensitive)

如果你需要从你的字典数组中创建一个字典，你需要使用forEach迭代结果并从中重建字典：

If you need to create a dictionary from your array of dictionaries, you would need to use forEach to iterate through the result and rebuild your dictionary from it:

let facilityDict: [Int: [String: String]] = [
    17: ["id": "199", "facilitycode": "036", "location_name": "Centerpoint Medical Offices"],
    41: ["id": "223", "facilitycode": "162", "location_name": "Dark Ridge Medical Center"],
    14: ["id": "196", "facilitycode": "023", "location_name": "Spinnerpark"],
    20: ["id": "202", "facilitycode": "048", "location_name": "Educational Theater"],
    30: ["id": "212", "facilitycode": "090", "location_name": "Partner Medical Offices"],
    49: ["id": "231", "facilitycode": "223", "location_name": "GreenBay Administrative Offices"]]

var filtered: [Int: [String: String]] =  [:]

facilityDict.filter{$0.value.contains{$0.value.contains("AR", options: .caseInsensitive)}}.forEach{filtered[$0.key] = $0.value}

print(filtered)  // [30: ["id": "212", "facilitycode": "090", "location_name": "Partner Medical Offices"], 41: ["id": "223", "facilitycode": "162", "location_name": "Dark Ridge Medical Center"], 14: ["id": "196", "facilitycode": "023", "location_name": "Spinnerpark"]]

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