适用于OSX的Python evdev [英] Python evdev equivalent for OSX

问题描述

我编写了一个Python脚本，该脚本轮询evdev的HID条码扫描器(模拟键盘):该脚本在Linux平台(Ubuntu)上运行良好.是否有适用于evdev的OS X Python等效版本，可允许对现有python脚本进行较小的移植?

I have written a python script that polls evdev for a HID barcode scanner (emulates a keyboard): the script works well on Linux platforms (Ubuntu). Is there an OS X Python equivalent for evdev that would allow minor porting of the existing python script?

如果您具有Python经验并已将其配置为HID设备输入，请在您的回复中注明.

If you have Python experience and have configured it for a HID device input, please indicate this in your response.

推荐答案

我使用 cython进行了简单的测试-hidapi (可作为pip install hidapi安装-请注意，这与注释中链接的内容不同，但功能似乎相似).我还从macports安装了hidapi-devel，但是我不确定这样做是否必要，因为在停用端口后它仍然可以工作.

I got a simple test working using cython-hidapi (installable as pip install hidapi - note this is different to the one linked in the comments but seems to be similar in function). I also had installed hidapi-devel from macports but I'm not sure that this is necessary as it continues to work after deactivating the port.

通过修改示例 try.py 来使用Microsoft USB无线键盘/鼠标设备的VID/PID如下

By modifying the example try.py to use the VID/PID of a Microsoft USB wireless keyboard/mouse device as follows

from __future__ import print_function

import hid
import time

print("Opening the device")

h = hid.device()
h.open(1118, 2048) # A Microsoft wireless combo keyboard & mouse

print("Manufacturer: %s" % h.get_manufacturer_string())
print("Product: %s" % h.get_product_string())
print("Serial No: %s" % h.get_serial_number_string())

try:
    while True:
        d = h.read(64)
        if d:
            print('read: "{}"'.format(d))
finally:
    print("Closing the device")
    h.close()

并使用$ sudo python try.py运行，我可以得到以下输出:

And running with $ sudo python try.py I was able to get the following output:

Opening the device
Manufacturer: Microsoft
Product: Microsoft® Nano Transceiver v2.0
Serial No: None
read: "[0, 0, 0, 0, 0, 0, 0, 0]"
read: "[0, 0, 0, 0, 0, 0, 0, 0]"
read: "[0, 0, 0, 0, 0, 0, 0, 0]"

--8<-- snip lots of repeated lines --8<--

read: "[0, 0, 0, 0, 0, 0, 0, 0]"
read: "[0, 0, 0, 0, 0, 0, 0, 0]"
read: "[0, 0, 21, 0, 0, 0, 0, 0]"
read: "[0, 0, 21, 0, 0, 0, 0, 0]"
read: "[0, 0, 21, 0, 0, 0, 0, 0]"
read: "[0, 0, 21, 0, 0, 0, 0, 0]"
read: "[0, 0, 0, 0, 0, 0, 0, 0]"
read: "[0, 0, 4, 0, 0, 0, 0, 0]"
read: "[0, 0, 4, 22, 0, 0, 0, 0]"
read: "[0, 0, 4, 22, 0, 0, 0, 0]"
read: "[0, 0, 4, 22, 0, 0, 0, 0]"
read: "[0, 0, 4, 22, 0, 0, 0, 0]"
read: "[0, 0, 4, 22, 0, 0, 0, 0]"
read: "[0, 0, 4, 0, 0, 0, 0, 0]"
read: "[0, 0, 4, 0, 0, 0, 0, 0]"
read: "[0, 0, 4, 9, 0, 0, 0, 0]"
read: "[0, 0, 4, 9, 0, 0, 0, 0]"
read: "[0, 0, 4, 9, 0, 0, 0, 0]"
read: "[0, 0, 4, 9, 0, 0, 0, 0]"
read: "[0, 0, 4, 9, 7, 0, 0, 0]"
read: "[0, 0, 4, 9, 7, 0, 0, 0]"
read: "[0, 0, 7, 0, 0, 0, 0, 0]"
^CClosing the device
Traceback (most recent call last):
  File "try.py", line 17, in <module>
    d = h.read(64)
KeyboardInterrupt

我正在使用的特定设备似乎被枚举为用于键盘&的多个HID设备.鼠标等等，所以您得到的似乎有点随机，但是对于条形码扫描仪来说，它应该很简单.

The particular device I'm using seems to enumerate as multiple HID devices for the keyboard & mouse amongst other things, so it seems to be a bit random which one you get, but for a barcode scanner it should be pretty straight forward.

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