检查文件夹是否包含glob [英] Check if folder contains glob
问题描述
在我的Mac上，我试图找出一种方法来检查服务器上已装入的卷，以查看目录是否通过将在launchd中设置为时间间隔的shell脚本接收到日志文件./p>
根据我的搜索记录，历史上我曾经使用过:
$DIR="/path/to/file"
THEFILES=(`find ./ -maxdepth 1 -name "*.log"`)
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
如果将shell脚本放置在该特定目录中，并且文件存在.但是，当我将脚本移到该目录之外并尝试:
THEFILES=(`find ./ -maxdepth 1 -name "*.log"`)
cd $DIR
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
我得到nothing的不变回报.我认为可能与深度有关，因此我将-maxdepth 1更改为-maxdepth 0，但仍然得到nothing.通过搜索，我遇到了"检查目录中是否存在某种文件类型/扩展名"并尝试:
THEFILES=$(ls "$DIR/.log" 2> /dev/null | wc -l)
echo $THEFILES
，但是我返回了常量0.当我进一步搜索时，遇到"从shell脚本检查目录中是否包含文件"，并尝试使用find与:
THEFILES=$(find "$DIR" -type f -regex '*.log')
cd $DIR
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
，返回空白.当我尝试时:
if [ -n "$(ls -A $DIR)" ]; then
echo "exists"
else
echo "nothing"
fi
我得到一个空白终端.在此 answer 上，我的Mac上没有prune或shopt.因此，如何检查已挂载服务器的目录，以查看是否存在具有特定扩展名的特定文件，而该文件不会从隐藏文件中返回错误信息?
每条评论，我都尝试通过以下方式消除深度:
THEFILES=$(find ./ -name "*.log")
但是我得到一个空白的返回，但是如果我在其中放一个.log文件，它会运行，但是我不明白为什么除非考虑隐藏文件，否则为什么不返回nothing.感谢 l'L ，我了解到-prune在find的实用程序中，但是当我尝试时:
if [ -n "$(find $DIR -prune -empty -type d)" ]; then
当存在一个LOG文件时，我得到的常量返回值为nothing.
您提出的每个答案都确实可以正常工作！
我没有使用-maxdepth选项，如果仅检查$DIR下的文件而不是其子目录对您很重要，请随时将-maxdepth 1添加到对find的任何调用中./p>
使用 mklement0 指出的小写变量，以避免与环境变量发生冲突.
答案1
您设置了dir，但改用了./ ...
dir="/path/to/dir"
# Create an array of filenames
files=( $(find "$dir" -name "*.log") )
if [ ${#files[@]} -gt 0 ]; then # if the length of the array is more than 0
echo "exists"
else
echo "nothing"
答案2
您在运行查找后使用cd $dir ...
dir="path/to/dir"
cd "$dir"
files=( $(find -name "*.log") )
if [ ${#files[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
答案3
您在'.log'之前忘记了'*'...看看偷偷摸摸
dir="/path/to/dir"
# print all the files in "$DIR" that end with ".log"
# and count the number of lines
nbfiles=$(ls "$dir/"*.log 2> /dev/null | wc -l) # nbfiles is an integer
if [ $nbfiles -gt 0 ]; then
echo "exists"
else
echo "nothing
fi
答案4
find 的macOS手册页建议regex默认使用基本正则表达式:
-E
解释后跟-regex和-iregex的正则表达式 选项作为扩展(现代)正则表达式而不是 基本的正则表达式(BRE).
您在*之前缺少.； cd $dir并不是必需的，因为您将$dir用作find的参数；并且您不会将find的输出存储在数组中，因此无法检查数组的长度.
# The output of find is stored as a string
files=$(find "/path/to/dir" -type f -regex '.*\.log')
if [ -n "$files" ]; then # Test that the string $files is not empty
echo "exists"
else
echo "nothing"
fi
On my Mac I am trying to figure out a way to check a mounted volume to a server to see if the directory receives a log file through a shell script that will be used in launchd set to a time interval.
From my searches and historically I've used:
$DIR="/path/to/file"
THEFILES=(`find ./ -maxdepth 1 -name "*.log"`)
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
If the shell script is placed inside that particular directory and the files are present. However, when I move the script outside of that directory and try:
THEFILES=(`find ./ -maxdepth 1 -name "*.log"`)
cd $DIR
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
I get a constant return of nothing. I thought it might be in regards to the depth so I changed -maxdepth 1 to -maxdepth 0 but I still get nothing. Through searching I ran across "Check whether a certain file type/extension exists in directory" and tried:
THEFILES=$(ls "$DIR/.log" 2> /dev/null | wc -l)
echo $THEFILES
but I'm returned a constant 0. When I searched further I ran across "Checking from shell script if a directory contains files" and tried a variation using find with:
THEFILES=$(find "$DIR" -type f -regex '*.log')
cd $DIR
if [ ${#THEFILES[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
with a blank return. When I try:
if [ -n "$(ls -A $DIR)" ]; then
echo "exists"
else
echo "nothing"
fi
I get a blank terminal returned. On this answer I dont have prune or shopt on my Mac. So how I can I check a mounted server's directory to see if a particular file with a specific extension exists that will not give a false return from hidden files?
EDIT:
Per comment I tried removing the depth with:
THEFILES=$(find ./ -name "*.log")
but I get a blank return but if I drop a .log file in there it runs but I don't understand why else isn't returning nothing unless it's considering the hidden files. Thanks to l'L'l I learned -prune was in find's utility but when I try:
if [ -n "$(find $DIR -prune -empty -type d)" ]; then
I get a constant return of nothing when there is a LOG file present.
Each of your proposed answer is really close to working!
I didn't use the -maxdepth option, if it is important to you to only check the files under $DIR but not its subdirectories, feel free to add -maxdepth 1 to any call to find.
Use lowercase variables as pointed by mklement0 to avoid conflicts with environment variables.
Answer 1
You set dir, but use ./ instead...
dir="/path/to/dir"
# Create an array of filenames
files=( $(find "$dir" -name "*.log") )
if [ ${#files[@]} -gt 0 ]; then # if the length of the array is more than 0
echo "exists"
else
echo "nothing"
Answer 2
You use cd $dir after running find...
dir="path/to/dir"
cd "$dir"
files=( $(find -name "*.log") )
if [ ${#files[@]} -gt 0 ]; then
echo "exists"
else
echo "nothing"
fi
Answer 3
you forgot a '*' before the '.log'... Have a look a the documentation for globbing
dir="/path/to/dir"
# print all the files in "$DIR" that end with ".log"
# and count the number of lines
nbfiles=$(ls "$dir/"*.log 2> /dev/null | wc -l) # nbfiles is an integer
if [ $nbfiles -gt 0 ]; then
echo "exists"
else
echo "nothing
fi
Answer 4
The macOS man page of find suggests that regex uses Basic Regular Expressions by default:
-E
Interpret regular expressions followed by -regex and -iregex options as extended (modern) regular expressions rather than basic regular expressions (BRE's).
You are missing a . before the * ; the cd $dir is not necessary since you pass $dir as an argument to find ; and you don't store the output of find in an array, so you can't check the length of the array.
# The output of find is stored as a string
files=$(find "/path/to/dir" -type f -regex '.*\.log')
if [ -n "$files" ]; then # Test that the string $files is not empty
echo "exists"
else
echo "nothing"
fi
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