PHP递归函数在变量有值的情况下返回null [英] Php recursive function return null while variable have value

问题描述

此函数返回NULL，而$ alias在第二次递归中具有值. 在第一次调用时，它返回所需的值，但在第一次调用时如果不匹配，它将首先在$ alias变量的avilable中递归所需的值，但不返回任何内容.

This function returns NULL while $alias having value in second recursion. In first call it return the required value but when first if not matched and it recurse first the required value in avilable in $alias variable but it does not return anything.

public function checkAlias($fname='',$lname=''){

        if(!empty($fname)){
        $fname = mysql_real_escape_string($fname);
        }
        if(!empty($lname)){
        $lname = mysql_real_escape_string($lname);
        }

    $alias = strtolower($fname).strtolower($lname);
    $sql = "Select ALIAS from table where ALIAS = '$alias'";
    $query = mysql_query($sql);
    $row = mysql_fetch_row($query);
    $string_length = strlen($alias) - 1;
    $result_string = substr($alias,0,$string_length);

    if(!$row){
            print $alias;   // is printing value 
        return $alias;  // but here it returns null
    }else{
        $this->checkAlias($result_string);
        } 
    }

推荐答案

您忘了返回递归调用的结果:

You forgot to return the result of the recursion call:

return $this->checkAlias($result_string);

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