如何禁用Net Core 2.1+中的预编译视图以进行调试? [英] How to disable precompiled views in net core 2.1+ for debugging?

问题描述

昨天我更新到了net core 2.1.

Yesterday I updated to net core 2.1.

现在，如果我正在调试，则视图将被预编译，这在启动过程中当然会花费很长时间....是否有可能回到以前的行为，即是否需要及时编译视图?

Now if I am debugging, the views getting precompiled, which ofcourse takes a long time during startup... Is it possible to fall back to the previous behavior, where the Views are compiled just in time, if it is needed?

我在csproj中没有与预编译相关的参考.是来自meta包的东西吗?

I have no reference related to precompilation in my csproj. Is it something that comes from the meta package?

  <ItemGroup>
    <PackageReference Include="JetBrains.Annotations" Version="11.1.0" />
    <PackageReference Include="Microsoft.AspNetCore.All" Version="2.1.0" />
    <PackageReference Include="Microsoft.EntityFrameworkCore.Tools" Version="2.1.0" PrivateAssets="All" />
    <PackageReference Include="Swashbuckle.AspNetCore" Version="2.5.0" />
    <!--<PackageReference Include="Microsoft.AspNetCore.Mvc.Razor.ViewCompilation" Version="2.0.0" PrivateAssets="All" />-->
  </ItemGroup>

推荐答案

.net核心> = 2.1&& < 3

这可以使用属性

.net core >= 2.1 && < 3

This can be accomplished using the property RazorCompileOnBuild in the .csproj file:

<PropertyGroup>
  <TargetFramework>netcoreapp2.1</TargetFramework>
  <RazorCompileOnBuild>false</RazorCompileOnBuild>
  <RazorCompileOnPublish>true</RazorCompileOnPublish>
</PropertyGroup>

这样，Razor文件仅在发布期间进行预编译.

This way the Razor files are only precompiled during publishing.

根据用例，您还希望根据构建配置进行配置:

Depending on the usecase you also want to configure this depending on the build configuration:

<PropertyGroup Condition="'$(Configuration)' == 'Debug'">
  <RazorCompileOnBuild>false</RazorCompileOnBuild>
  <RazorCompileOnPublish>true</RazorCompileOnPublish>
</PropertyGroup>

.net核心> = 3

Microsoft创建了一个Nuget程序包.这是在此处记录的.

只需在 Microsoft.AspNetCore.Mvc.Razor.RuntimeCompilation > .csproj 文件.

<PackageReference
    Include="Microsoft.AspNetCore.Mvc.Razor.RuntimeCompilation"
    Version="3.1.0"
    Condition="'$(Configuration)' == 'Debug'" />

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