AWK输出到bash数组 [英] AWK output to bash Array

问题描述

我正在尝试将简单命令的内容放入bash数组中，但是我有点麻烦.

Im trying to put the contents of a simple command in to a bash array however im having a bit of trouble.

df -h | awk '{ print  $5" "$6 }'

给出了我系统上文件系统中使用的百分比 输出看起来像这样:

gives percentage used in the file systems on my system output looks like this:

1% /dev
1% /dev/shm
1% /var/run
0% /var/lock
22% /boot
22% /home
22% /home/steve

然后我想将这些行中的每行放入bash数组中 array = $(df -h | awk'{print $ 5 $ 6}')

I would then like to put each of these lines into a bash array array=$(df -h| awk '{ print $5 $6 }')

但是，当我打印出数组时，我得到以下信息:

However when I print out the array I get the following:

5%
/
1%
/dev
1%
/dev/shm
1%
/var/run
0%
/var/lock
22%
/boot
22%
/home
22%
/home/steve

Bash根据空格形成数组，而不是换行符，我该如何解决?

Bash is forming the array based on white spaces and not line breaks how can i fix this?

推荐答案

您需要重置IFS变量(用于数组的分度符).

You need to reset the IFS variable (the delimeter used for arrays).

OIFS=$IFS #save original
IFS=','
df -h | awk '{ print $5" "$6"," }'

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