Bash 将 awk 的输出捕获到数组中 [英] Bash capturing output of awk into array

问题描述

我遇到了一个小问题.我有一个命令将输出通过管道传输到 awk，但我想将输出一一捕获到数组中.

I am stuck on a little problem. I have a command which pipes output to awk but I want to capture the output of to an array one by one.

我的例子:

myarr=$(ps -u kdride | awk '{ print $1 }')

但这将我的所有输出捕获到一个用逗号分隔的巨大字符串中:

But that capture all my output into one giant string separated by commas:

output: PID 3856 5339 6483 10448 15313 15314 15315 15316 22348 29589 29593 32657 1

我还尝试了以下方法:

IFS=","
myarr=$(ps -u kdride | awk '{ print $1"," }')

But the output is: PID, 3856, 5339, 6483, 10448, 15293, 15294, 15295, 15296, 22348, 29589, 29593, 32657,
1

我希望能够将每个单独的 pid 捕获到它自己的数组元素中.设置 IFS = '\n' 不会做任何事情并保留我的原始输出.我需要做哪些改变才能使这项工作发挥作用?

I want to be able to capture each individual pid into its own array element. Setting IFS = '\n' does not do anything and retains my original output. What change do I need to do to make this work?

推荐答案

添加额外的括号，如下所示:

Add additional parentheses, like this:

myarr=($(ps -u kdride | awk '{ print $1 }'))

# Now access elements of an array (change "1" to whatever you want)
echo ${myarr[1]}

# Or loop through every element in the array
for i in "${myarr[@]}"
do
   :
  echo $i
done

另见 bash — 数组.

See also bash — Arrays.

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