将多行输出捕获到 Bash 变量中 [英] Capturing multiple line output into a Bash variable

问题描述

我有一个输出以下内容的脚本myscript":

I've got a script 'myscript' that outputs the following:

abc
def
ghi

在另一个脚本中，我调用:

in another script, I call:

declare RESULT=$(./myscript)

和 $RESULT 获取值

abc def ghi

有没有办法用换行符或 ' ' 字符存储结果，以便我可以用 'echo -e' 输出它?

Is there a way to store the result either with the newlines, or with ' ' character so I can output it with 'echo -e'?

推荐答案

实际上，RESULT 包含了你想要的——演示:

Actually, RESULT contains what you want — to demonstrate:

echo "$RESULT"

你所展示的就是你从中得到的:

What you show is what you get from:

echo $RESULT

<小时>

正如评论中所指出的，不同之处在于 (1) 变量的双引号版本 (echo "$RESULT") 完全按照它在变量 — 换行符、制表符、多个空格和所有 — 而 (2) 不带引号的版本 (echo $RESULT) 用一个空格替换一个或多个空格、制表符和换行符的每个序列.因此，(1) 保留了输入变量的形状，而 (2) 创建了一个潜在的非常长的单行输出，其中单词"由单个空格分隔(其中单词"是非空白字符的序列；需要'不能是任何单词中的任何字母数字).

---

As noted in the comments, the difference is that (1) the double-quoted version of the variable (echo "$RESULT") preserves internal spacing of the value exactly as it is represented in the variable — newlines, tabs, multiple blanks and all — whereas (2) the unquoted version (echo $RESULT) replaces each sequence of one or more blanks, tabs and newlines with a single space. Thus (1) preserves the shape of the input variable, whereas (2) creates a potentially very long single line of output with 'words' separated by single spaces (where a 'word' is a sequence of non-whitespace characters; there needn't be any alphanumerics in any of the words).

这篇关于将多行输出捕获到 Bash 变量中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！