如何在批处理脚本中找到应用程序的完整路径 [英] How do I find full path to an application in a batch script

问题描述

如何在批处理脚本中找到应用程序XYZ的完整路径(如果已安装)

How do I in a batch script find the full path to application XYZ if it is installed

说明:

1. 该应用程序不在PATH中
2. 在这种情况下，我所拥有的只是它的名字"ISTool.exe"，我想得到 C:\ Program \ ISTool \ ISTool.exe

推荐答案

我从其他人那里得到的答案有效(但是速度较慢或使用了多余的文件)并且适用于任何exe，但并不真正适合我的需求.

The answers I got from others worked (but slow or used extra files) and worked for any exe but didn't really suit my needs.

因为我想找到一个特定的exe，所以我使用注册查询.我找到了一个包含要查找的数据的密钥，并将其提取出来.

Since I wanted to find a particular exe I went looking in the registry using REG QUERY instead. I found a key that contained the data I wanted to find and extracted that.

结果很快，只有几行代码，但不是很漂亮，也不可重用.

The result is fast, has few lines of code but is not very pretty nor reusable.

简短示例:

@ECHO off
SETLOCAL
set found=
FOR /F "tokens=1-3 delims= " %%a IN ('REG QUERY "HKEY_CLASSES_ROOT\Applications\ISTool.exe\shell\OpenWithISTool\command"') DO (
 set found=%%c
)

for /f "tokens=1-2" %%a in ("%found%") do (
 set my_exe=%%a
)
echo %my_exe%
ENDLOCAL

这将导致"C:\Program\ISTool\ISTool.exe"(带引号)
注意:上面的delims =后跟一个制表符

This results in "C:\Program\ISTool\ISTool.exe" (with quotes)
Note: delims= above is followed by a tab-char

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