如何从里面找到C ++ Linux程序的完整路径？ [英] How to find the full path of the C++ Linux program from within?

问题描述

我有这个要求，我需要从里面找到C ++程序的完整路径。对于Windows，我有以下解决方案。 argv [0]可能包含或不包含完整路径。但我需要确定。

I have this requirement where I need to find the full path for the C++ program from within. For Windows, I have the following solution. The argv[0] may or may not contain the full path. But I need to be certain.

TCHAR drive[_MAX_DRIVE], dir[_MAX_DIR], base[_MAX_FNAME], ext[_MAX_EXT];
TCHAR fullPath[255+1];
_splitpath(argv[0],drive,dir,base,ext);
SearchPath(NULL,base,ext,255,fullPath,NULL);

上述代码的Linux（gcc）

What is the Linux (gcc) equivalent for the above code? Would love to see a portable code.

推荐答案

在Linux（Posix？）上有一个符号链接

On Linux (Posix?) you have a symbolic link /proc/self/exe which links to the full path of the executable.

在Windows上，使用 /msdn.microsoft.com/en-us/library/ms683197%28v=vs.85%29.aspx> GetModuleFileName 。

On Windows, use GetModuleFileName.

不要依靠 argv [0] ，这不能保证是有用的。

Never rely on argv[0], which is not guaranteed to be anything useful.

请注意，路径和文件系统不是语言的一部分，因此必须是平台相关功能。

Note that paths and file systems are not part of the language and thus necessarily a platform-dependent feature.

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