批处理脚本-查找文件中是否缺少字符串，显示输出 [英] Batch Script - Find if String is missing in a file, show output

问题描述

我有10个文件夹的群集，每个文件夹包含1000个程序文件.我需要在这些文本文件中搜索"MISSING"字符串.所有文件必须以$ O123456.MIN％开头(123456是随机文件名).我知道如何查找字符串是否存在，但是如何识别字符串是否不存在?

I have cluster of 10 folders, each with 1000 program files. I need to search these text files for a MISSING string. All files must start with $O123456.MIN% (123456 being random file names). I know how to find if the string exists, but how do I identify if the string does not exist?

一旦确定了哪个文件缺少字符串，我希望将报告或该文件的副本移到另一个文件夹中.

Once it is identified, what file is missing the string, I would like eather a report or a copy of that file, moved to another folder.

推荐答案

您的要求不清楚.我假设以下情况:

Your requirements are not clear. I am assuming the following:

1-您的10个文件夹的群集"由某个根文件夹中的所有文件夹组成.

1 - Your "cluster" of 10 folders consists of all folders within a certain root folder.

2-您的文本文件均具有.txt扩展名

2 - Your text files all have .txt extensions

3-您要报告指定文件夹中的所有文件，其中第一行不是以$O*.MIN%开头，其中*表示任意1个或多个字符，并且O和MIN区分大小写.

3 - You want to report all files within the specified folders where the first line does not start with $O*.MIN%, where * represents any 1 or more characters, and O and MIN are case sensitive.

@echo off
setlocal
set "rootFolder=c:\yourRootPath"
set "fileMask=*.txt"
set "outFile=missing.txt"

>"%outFile%" (
  for /d %%D in ("%rootFolder%") for %%F in ("%%D\%fileMask%") do (
    findstr /nbr "$O..*\.MIN%%" "%%F" | findstr /bl "1:" >nul || echo %%F
  )
)

如果您的实际要求不同，则可能不需要太多代码更改.例如，执行以下任何更改都是微不足道的:

If your actual requirements are different, it probably won't take much code change. For example, any of the following changes would be trivial to implement:

• 更改文件掩码
• 使搜索大小写不敏感
• 递归处理根文件夹中的所有文件夹
• 处理特定文件夹的列表
• 限制随机文件中可以使用哪些字符和/或多少个字符(您的0123456)

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