使用 Bash 脚本查找文件中字符串的行号 [英] Using Bash Script to Find Line Number of String in File

问题描述

如何使用 bash 脚本查找字符串出现的行号?

How can I use a bash script to find the line number where a string occurs?

例如，如果一个文件看起来像这样，

For example if a file looked like this,

Hello I am Isaiah
This is a line of text.
This is another line of text.

然后我运行脚本来查找字符串line"，它会输出数字 2，因为它是第一次出现.

and I ran the script to look for the string "line" it would output the number 2, as it is the first occurance.

推荐答案

鉴于您的示例只打印字符串第一次出现的行号，也许您正在寻找:

Given that your example only prints the line number of the first occurrence of the string, perhaps you are looking for:

awk '/line/{ print NR; exit }' input-file

如果您确实想要所有出现的次数(例如，如果您的示例所需的输出实际上是2 3 ")，请省略 exit.

If you actually want all occurrences (eg, if the desired output of your example is actually "2 3 "), omit the exit.

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