用格式值替换DecimalFormat的分组分隔符 [英] Replace grouping separator of DecimalFormat in formatted value

问题描述

我已经使用DecimalFormat df = new DecimalFormat("#,###.00");格式化BigDecimal.

现在，我想使用该格式化值(例如为'1 250,00')来创建new BigDecimal.我已经尝试过了:

Now, I want to use that formatted value (say it is '1 250,00') to create new BigDecimal. I've tried this:

BigDecimal result = new BigDecimal(model.getValue().replace(",",".").replace(" ",""));

但是不会替换1 250.00中1和2之间的space.我该如何解决?

But that space between 1 and 2 in 1 250.00 is not replaced. How can I fix it?

示例:

DecimalFormat df = new DecimalFormat("#,###.00");
BigDecimal example = new BigDecimal("1250");
String str = df.format(example);
System.out.println(str.replace(",",".").replace(" ",""));

推荐答案

DecimalFormat Javadoc指定符号,是分组分隔符.默认情况下，对于您的语言环境，此分隔符不是一个空格，而是一个不间断的空格.可以通过以下代码显示:

DecimalFormat Javadoc specifies that the symbol , is the grouping separator. By default, for your locale, this separator is not a space but a non-breaking space. This can be shown by the following code:

DecimalFormatSymbols symbols = new DecimalFormatSymbols(Locale.forLanguageTag("ru-RU"));
System.out.println((int) symbols.getGroupingSeparator());

您会看到打印的int是160，它对应于非打破空间" .

You will see that the int printed is 160, which corresponds to "Non-breaking space" in ISO-8859-1.

要删除该字符，我们可以使用其 Unicode表示形式并替换为:

To remove that character, we can use its Unicode representation and replace that:

DecimalFormat df = new DecimalFormat("#,###.00");
String str = df.format(new BigDecimal("1250"));
System.out.println(str.replace(",", ".").replace("\u00A0", ""));

对于更通用的解决方案，不依赖于当前的语言环境，我们可以检索分组分隔符并直接使用它:

For a more general solution, not depending on the current locale, we could retrieve the grouping separator and use that directly:

DecimalFormat df = new DecimalFormat("#,###.00");
String groupingSeparator = String.valueOf(df.getDecimalFormatSymbols().getGroupingSeparator());
String str = df.format(new BigDecimal("1250"));
System.out.println(str.replace(",", ".").replace(groupingSeparator, ""));

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