尝试在C#中的UInt16上执行按位不(〜)时出错 [英] Error when trying to perform a bitwise not (~) on a UInt16 in C#

问题描述

出于某种原因，我只是不了解(或看到)其工作原理:

For some reason, I am simply not understanding (or seeing) why this works:

UInt32 a = 0x000000FF;
a &= ~(UInt32)0x00000001;

但这不是:

UInt16 a = 0x00FF;
a &= ~(UInt16)0x0001;

它给出错误常量值-(某些数字)无法转换为UInt16".有人可以解释这是为什么以及如何解决该问题吗?

it gives the error 'constant value -(some number) cannot be converted to a UInt16'. Can someone explain why this is and how to work around the problem?

推荐答案

按位取反可将结果提升为int，尽管进行了强制转换.您可以通过按位求和并将按位求反的结果降低到低16位来解决此问题，如下所示:~0x0001 & 0xFFFF.

The bitwise negation promotes the result to a int, despite the cast. You can overcome this by bitwise and-ing the result of the bitwise negation to the lower 16 bits, like this: ~0x0001 & 0xFFFF.

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