ORA-01465:使用BLOB时，oracle中的十六进制数字无效 [英] ORA-01465: invalid hex number in oracle while using BLOB

问题描述

我正在Oracle 11g中设计一个数据库.我设计了带有字段的表格，

i am designing a database in oracle 11g. I have designed a table with fields,

CUST_ID, NUMBER(5) //this is a foreign key
Review, BLOB //to store big strings 
Date, SYSDATE

现在，当我尝试在表中插入数据时-

now when i'm trying to insert data in the table like-

insert into "ReviewTable" values ( 3, 'hello, this is the first review',SYSDATE)

它给出[Err] ORA-01465:无效的十六进制数. 如果有人可以帮助我解决错误?

it gives [Err] ORA-01465: invalid hex number. If someone can help me with the error?

推荐答案

您将字符串转换为BLOB，可以通过包utl_raw.cast_to_raw进行此操作，也可以通过to_clob('mystring')将varchar转换为clob，然后在其中使用过程DBMS_LOB.convertToBlob您的代码

you cast your string into BLOB, you can do this via package utl_raw.cast_to_raw or convert varchar to clob via to_clob('mystring') and then use procedure DBMS_LOB.convertToBlob in your code

但是如果您要使用字段作为字符串，为什么不将它们另存为CLOB?

but if you are going to use the fields for string why don`t save them as a CLOB?

以下是两个带有BLOB和CLOB字段的示例

Here are 2 examples below with BLOB and CLOB fields

BLOB

create table ReviewTable( CUST_ID NUMBER(5)
,Review  BLOB  
,Dt Date);

insert into ReviewTable values ( 3, utl_raw.cast_to_raw('hello, this is the first review'),SYSDATE);

CLOB

create table ReviewTable2( CUST_ID NUMBER(5)
,Review  CLOB  
,Dt Date);

insert into ReviewTable2 values ( 3, 'hello, this is the first review',SYSDATE);

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