如何比较单个（浮点）类型？ [英] How to compare single (floating point) types?

问题描述

我的场景中有6个InputField。他们的内容类型是十进制。

I have 6 InputFields in my scene. Their content type is decimal.

我从这些输入字段中获取值，并检查它们的总和是否等于100.02。我在所有参数中都输入了16.67。

I fetch values from these input fields and check if their sum is equal to 100.02. I enter 16.67 in all of them.

    float fireP   =  float.Parse(firePercentage.text);
    float waterP  =  float.Parse(waterPercentage.text);
    float lightP  =  float.Parse(lightPercentage.text);
    float nightP  =  float.Parse(nightPercentage.text);
    float natureP =  float.Parse(naturePercentage.text);
    float healthP =  float.Parse(healthPercentage.text);

    float total = fireP + waterP + lightP + nightP + natureP + healthP;

   if (total == 100.02f)
   {
     Debug.Log("It's equal");
   }
   else
   {
     Debug.Log(" Not equal. Your sum is = " + total);
   }

我在控制台中收到不相等。您的总和= 100.02日志。
无论如何都知道为什么会发生这种情况？

I am getting " Not equal. Your sum is = 100.02" in my console log. Anyways has any idea why this might be happening ?

推荐答案

最接近 16.67的 float 是 16.6700000762939453125 。

最近的 float 至 100.02 是 100.01999664306640625

前者自身5次与后者完全不同，因此它们将不相等。

Adding the former to itself 5 times is not exactly equal to the latter, so they will not compare equal.

在此特殊情况，将 tolerance 与1e-6的顺序进行比较可能是可行的方法。

In this particular case, comparing with a tolerance in the order of 1e-6 is probably the way to go.

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