完美的转发容器元素 [英] Perfect forwarding container element
问题描述
类似于此问题,但不是完美的转发成员对象,我想知道如何完善STL容器的转发元素,即类似于
Similar to this question, but instead of perfect forwarding member of an object, I would like to know how to perfect forwarding elements of an STL container, i.e. similar to
struct X {};
void f(X&);
void f(X&&);
template <typename Vector>
void g(Vector&& v, size_t i) {
if (is_lvalue_reference<Vector>::value) {
f(v[i]);
} else {
f(move(v[i]));
}
}
推荐答案
namespace detail {
template<class T, class U>
using forwarded_type = std::conditional_t<std::is_lvalue_reference<T>::value,
std::remove_reference_t<U>&,
std::remove_reference_t<U>&&>;
}
template<class T, class U>
detail::forwarded_type<T,U> forward_like(U&& u) {
return std::forward<detail::forwarded_type<T,U>>(std::forward<U>(u));
}
template <typename Vector>
void g(Vector&& v, size_t i) {
f(forward_like<Vector>(v[i]));
}
演示。在实现中使用 std :: forward
自动防止您将rvalue进行危险的左值化。
Demo. Using std::forward
in the implementation automatically prevents you from doing a dangerous forward of rvalue as lvalue.
您的实际用例
我想从中创建
vector< T>
vector
,vector< U2>
,....,其中
每个元素T
由U1,U2,...
构造。
vector< Ui>
的每个数组可以是&
或& ;&
,我希望Ui
能够完美地转发
。
I'd like to create
vector<T>
fromvector<U1>
,vector<U2>
, ...., where each elementT
is constructed fromU1, U2, ...
. Each array ofvector<Ui>
could be either&
or&&
, and I'd like theUi
to be perfectly forwarded.
这就像
template<class T, class...Vectors>
std::vector<T> make_vector(Vectors&&...vectors){
auto n = std::min({vectors.size()...});
std::vector<T> ret;
ret.reserve(n);
for(decltype(n) i = 0; i < n; ++i)
ret.emplace_back(forward_like<Vectors>(vectors[i])...);
return ret;
}
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