使用别名的静态成员函数？ [英] using alias for static member functions?

问题描述

在C ++中是否有别名别名静态成员函数的方法？我希望能够将其应用到范围内，这样就不必完全限定名称。

Is there a way to alias a static member function in C++? I would like to be able to pull it into scope so that I do not need to fully qualify the name.

本质上类似于：

struct Foo {
  static void bar() {}
};

using baz = Foo::bar; //Does not compile

void test() { baz(); } //Goal is that this should compile

我的第一个想法是使用 std :: bind （如 auto baz = std :: bind（Foo :: bar）; ）或函数指针（如 auto baz = Foo :: bar; ），但这并不令人满意，因为对于每个要使用别名的函数，我都需要为此单独创建一个变量函数，或者使别名变量在全局/静态范围内可用。

My first thought was to use std::bind (as in auto baz = std::bind(Foo::bar);) or function pointers (as in auto baz = Foo::bar;), but that is unsatisfactory because for each function I want to be able to use the alias in, I need to make a separate variable just for that function, or instead make the alias variable available at global/static scope.

推荐答案

使用不是此处的正确工具。只需使用 auto baz =& Foo :: bar 声明您的别名（如果需要，可以声明为全局别名）。

using is not the correct tool here. Simply declare your alias (as global if you need to) with auto baz = &Foo::bar.

根据注释中的建议，也可以使 constexpr 尽可能在编译时以常量表达式提供它。

As suggested in the comments, you can also make it constexpr to have it available, when possible, at compile-time in constant expressions.

struct Foo {
  static void bar() { std::cout << "bar\n"; }
};

constexpr auto baz = &Foo::bar; 

void test() { baz(); }

int main() 
{
    test();
}

演示

Demo

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