将类中的所有双打初始化为零 [英] Initializing all doubles in a class to zero

问题描述

我有一个只有双成员变量的结构，例如

I have a struct that only has double member variables, e.g.

struct foo { double a, b, c; };

另一个类具有 std :: vector< foo> v 成员，该成员在初始化器列表中调用 std :: vector< foo> :: vector（size_t）构造函数。

Another class has a std::vector<foo> v member that calls the std::vector<foo>::vector(size_t) constructor in the initializer list.

我想做的是为 foo 编写一个默认构造函数，以便将其中的所有双精度数初始化为零，而不必

What I'd like to do is write a default constructor for foo so that all the doubles in it are initialized to zero, without having to write

foo(): a(0), b(0), c(0) { }

我一直需要向 foo 添加更多变量让它们成为 std :: array< double> 之类的容器的元素没有意义，因为它们都具有不同的用途。

I keep needing to add more variables to foo, but it doesn't make sense to have them be elements of a container like std::array<double>, because they all serve distinct purposes.

推荐答案

由于已将其标记为C ++ 14，因此可以像这样初始化成员变量，而不必在构造函数中对其进行初始化：

Since you've tagged this as C++14, you can initialize member variables like this without having to initialize them in a constructor:

struct foo {
    double a = 0.0;
    double b = 0.0;
    double c = 0.0;
};

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