通过os.system推送 [英] pushd through os.system
问题描述
我正在使用crontab为我的Minecraft服务器运行维护脚本。在大多数情况下，它工作正常，除非crontab尝试使用重新启动脚本。如果我手动运行重新启动脚本，则不会有任何问题。因为我认为它与路径名有关，所以我试图确保它始终在minecraft目录中执行任何minecraft命令。因此，我将命令包含在push / popd中：
I'm using a crontab to run a maintenance script for my minecraft server. Most of the time it works fine, unless the crontab tries to use the restart script. If I run the restart script manually, there aren't any issues. Because I believe it's got to do with path names, I'm trying to make sure it's always doing any minecraft command FROM the minecraft directory. So I'm encasing the command in pushd/popd:
os.system("pushd /directory/path/here")
os.system("command to sent to minecraft")
os.system("popd")
以下是一个互动会话，使我的世界脱离了困境。一个简单的 ls测试。如您所见，它根本不是从pushd目录运行os.system命令，而是从/ etc /运行python来说明我的观点的/ etc /目录。 ，所以我想知道我还能如何实现这一目标。谢谢！
Below is an interactive session taking minecraft out of the equation. A simple "ls" test. As you can see, it does not at all run the os.system command from the pushd directory, but instead from /etc/ which is the directory in which I was running python to illustrate my point.Clearly pushd isn't working via python, so I'm wondering how else I can achieve this. Thanks!
>>> def test():
... import os
... os.system("pushd /home/[path_goes_here]/minecraft")
... os.system("ls")
... os.system("popd")
...
>>> test()
~/minecraft /etc
DIR_COLORS cron.weekly gcrypt inputrc localtime mime.types ntp ppp rc3.d sasldb2 smrsh vsftpd.ftpusers
DIR_COLORS.xterm crontab gpm-root.conf iproute2 login.defs mke2fs.conf ntp.conf printcap rc4.d screenrc snmp vsftpd.tpsave
X11 csh.cshrc group issue logrotate.conf modprobe.d odbc.ini profile rc5.d scsi_id.config squirrelmail vz
adjtime csh.login group- issue.net logrotate.d motd odbcinst.ini profile.d rc6.d securetty ssh warnquota.conf
aliases cyrus.conf host.conf java lvm mtab openldap protocols redhat-release security stunnel webalizer.conf
alsa dbus-1 hosts jvm lynx-site.cfg multipath.conf opt quotagrpadmins resolv.conf selinux sudoers wgetrc
alternatives default hosts.allow jvm-commmon lynx.cfg my.cnf pam.d quotatab rndc.key sensors.conf sysconfig xinetd.conf
bashrc depmod.d hosts.deny jwhois.conf mail named.caching-nameserver.conf passwd rc rpc services sysctl.conf xinetd.d
blkid dev.d httpd krb5.conf mail.rc named.conf passwd- rc.d rpm sestatus.conf termcap yum
cron.d environment imapd.conf ld.so.cache mailcap named.rfc1912.zones pear.conf rc.local rsyslog.conf setuptool.d udev yum.conf
cron.daily exports imapd.conf.tpsave ld.so.conf mailman netplug php.d rc.sysinit rwtab shadow updatedb.conf yum.repos.d
cron.deny filesystems init.d ld.so.conf.d makedev.d netplug.d php.ini rc0.d rwtab.d shadow- vimrc
cron.hourly fonts initlog.conf libaudit.conf man.config nscd.conf pki rc1.d samba shells virc
cron.monthly fstab inittab libuser.conf maven nsswitch.conf postfix rc2.d sasl2 skel vsftpd
sh: line 0: popd: directory stack empty
===
（具有python 2.4的CentOS服务器）
=== (CentOS server with python 2.4)
推荐答案
每个shell命令在单独的进程中运行。它产生一个shell，执行pushd命令，然后shell退出。
Each shell command runs in a separate process. It spawns a shell, executes the pushd command, and then the shell exits.
只需在相同的shell脚本中编写命令：
Just write the commands in the same shell script:
os.system("cd /directory/path/here; run the commands")
子过程是一种更好的方法（也许） 模块：
from subprocess import Popen
Popen("run the commands", shell=True, cwd="/directory/path/here")
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