当引用成为引用对象时，如何使python对象自身或属性不分配给引用对象？ [英] How to make a python objects self or attribute not get assigned to the referencer object when it is references?

问题描述

我希望当一个对象被另一个对象，引用者的自身对象或其属性之一在引用者对象处不同时

I want when a object is referenced by another, the refernecer's self object or one of it's attributes to be different at the referencer object

这就是我想做的：

class MyClass:
    .
    .
    .
    .

a = MyClass()
b = a
print(b is a) #must print false
print(b == a) #must print true

#or
a = MyClass()
b = a
print(b.attr is a.attr) #must print false
print(b.attr == a.attr) #must print true

我如何实现这一目标，通常是在进行 a = b ， b 是对 a 的引用，值得赞赏的是，我希望 b 是 a 的副本/深拷贝，与属性

How can I achieve this, normally the when an assignment is made like a = b, b is a reference to a, any help would be appreciated, I want b to be a copy/deepcopy of a, same for the attribute

从现在开始感谢将要回答问题的人

Thanks from now for the people who will answer the question

注意：我正在使用CPython（Python的官方实现）版本Python 3.8

Note: I’m using CPython (the official implemention of Python) version Python 3.8

我愿意使用黑魔法

推荐答案

您不应尝试对重载进行任何操作因为那不是很pythonic。使用 deepcopy 函数或将其复制为构造函数。然后覆盖 __ eq __ 函数，以使两个变量测试相等。

You shouldn't try to do anything with overloading assignment as that's not very pythonic. Either use the deepcopy function or make a copy "constructor". Then override the __eq__ function so that the two variables test equal.

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