dply：在R中按字母顺序排列列 [英] dply: order columns alphabetically in R

问题描述

如果我有一个大的DF（数百个和数百个）的列，它们的col_names不同按字母顺序随机分布：

If I have a large DF (hundreds and hundreds) columns with different col_names randomly distributed alphabetically:

df.x <- data.frame(2:11, 1:10, rnorm(10))
colnames(df.x) <- c("ID", "string", "delta")

我如何按col_name字母顺序对所有数据进行垂直排序？

How would I order all of the data (vertically) by col_name alphabetically?

基本上，我有数百个CSV（sep = |）文本文件，需要将其列读入单个df中，按字母顺序对这些列进行排序，然后使用其他dplyf函数获得最终结果。除了如何按字母顺序排列列外，我已经弄清楚了所有这些内容。我不想按字母对列（上下）进行排序，而是按col_names及其对应数据的实际垂直方向排序。类似于在Excel中剪切和粘贴整个数据列。

Essentially, I have hundreds of CSV(sep="|") text files that I need to read their columns into a single df, order those columns alphabetically and then use some other dplyf functions to get a final result. I have all of this figured out except how to order the columns alphabetically. I do not want to sort the columns (up and down) by alphabet, rather, the actual vertical orientation of the col_names and their corresponding data. Analogous to cutting and pasting entire columns of data in Excel.

例如，我回顾了这种方法，但这是按字母顺序对行进行排序，这不是我所需要的。

For example I reviewed this approach but this is the "sort" the rows alphabetically bit, which is not what I'm looking to do.

如何按列对数据框进行排序？

谢谢！

推荐答案

尝试一下

df %>% select(noquote(order(colnames(df))))

或者只是

df[,order(colnames(df))]

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