Symfony 3-自动序列化DateTime对象 [英] Symfony 3 - automatically serialize DateTime object
本文介绍了Symfony 3-自动序列化DateTime对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在我的项目中,我有一些带有 createdAt
列的实体。
In my project I have some entity with createdAt
column.
//...
class Acme
{
/**
* @var DateTime
*
* @ORM\Column(name="created_at", type="datetime")
*/
protected $createdAt;
}
我已启用 FOSRestBundle
使用Symfony序列化器:
I have enabled FOSRestBundle
with Symfony serializer:
fos_rest:
disable_csrf_role: ROLE_API
param_fetcher_listener: true
body_listener: true
format_listener:
rules:
- { path: '/', fallback_format: json, prefer_extension: false }
routing_loader:
default_format: json
include_format: false
view:
view_response_listener: force
我选择 AcmeRepository
中的日期库:
public function methodName()
{
$qb = $this->createQueryBuilder('d');
$s = $qb->select('d.createdAt']);
return $s->getQuery()->getArrayResult();
}
结果,在我的控制器中:
And in result, in my controller:
$res = $em->getRepository('AppBundle:Acme')->methodName();
return $res;
返回json,而不是 [{ created_at: 2016 -04-04 12:13:13}]
我得到了:
It's returns json, but instead of [{"created_at": "2016-04-04 12:13:13"}]
i'm getting this:
[{"created_at":{"timezone":{"name":"UTC","location":{"country_code":"??","latitude":0,"longitude":0,"comments":""}},"offset":0,"timestamp":1459769277}]
我该如何解决
推荐答案
您可以使用适当的注释类型指定为FOS REST模块定义的类型的格式(选中此处文档)。例如:
You can specify the format of the Type defined for the FOS REST module with the proper annotation Type (check here the doc). As example:
use JMS\Serializer\Annotation\Type as JMS;
class Acme
{
/**
* @var DateTime
*
* @ORM\Column(name="created_at", type="datetime")
* @JMS\Type("DateTime<'Y-m-d'>")
*/
protected $createdAt;
}
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