如何在dotnet core中将动态对象序列化为JSON字符串？ [英] How to serialize a dynamic object to a JSON string in dotnet core?

问题描述

我正在将JSON有效负载传递给API控制器，并且其中一个字段是动态的，因为该字段需要作为JSON字符串再次传递给另一个API。 dotnet核心3.1中间层不必担心类型，因为有效负载会发生变化。

I am passing a JSON payload to an API Controller, and one of the fields is dynamic because the field needs to be passed again as a JSON string to another API. The dotnet core 3.1 middle layer shouldn't be concerned with typing, as the payload will change.

这是传递给API控制器的对象：

This is the object that is passed into the API Controller:

    public class GitHubAction
    {
        [JsonProperty("Title")]
        public string Title { get; set; }

        [JsonProperty("Enabled")]
        [JsonConverter(typeof(BooleanParseStringConverter))]
        public bool Enabled { get; set; }

        [JsonProperty("Action")]
        [JsonConverter(typeof(ExpandoObjectConverter))]
        public dynamic Action { get; set; }
    }

这里是动态的图片对象在VSCode中看起来像：

Here is a picture of that dynamic object looks like in VSCode:

当我使用 JsonConvert.SerializeObject（x.Action）; 时，字符串结果未正确转换，而是序列化为ValueKind： {\ ValueKind\：1} 。

When I use JsonConvert.SerializeObject(x.Action); the string result isn't being properly converted, but instead serializes to ValueKind: "{\"ValueKind\":1}".

我想要获取的是作为JSON字符串的操作对象值，它应该类似于 { createRepository：{ onboarding ：{ service：{ organization： foo， repositoryName： foo-2-service， description：测试服务。}}}}

What I want to get is the action object value as a JSON string, which should look like "{"createRepository":{"onboarding":{"service":{"organization":"foo","repositoryName":"foo-2-service","description":"A test service."}}}}"

是否有一个简单的序列化动态对象的解决方案？

Is there a simple solution for serializing a dynamic object?

推荐答案

我遇到了同样的问题，并使用System.Text.Json以这种方式解决了此问题

I had the same problem and I fixed it this way

using System.Text.Json;

string serializedObject = JsonSerializer.Serialize(x.Action); //Instead of use JsonConvert.SerializeObject(x.Action);

您必须使用<$ c来代替 Newtonsoft.Json $ c> System.Text.Json 。

Instead of Newtonsoft.Json you have to use System.Text.Json.

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