如何在 dotnet core 中将动态对象序列化为 JSON 字符串? [英] How to serialize a dynamic object to a JSON string in dotnet core?

问题描述

我正在将 JSON 有效负载传递给 API 控制器，其中一个字段是动态的，因为该字段需要作为 JSON 字符串再次传递给另一个 API.dotnet core 3.1 中间层不应该关心打字，因为有效载荷会改变.

I am passing a JSON payload to an API Controller, and one of the fields is dynamic because the field needs to be passed again as a JSON string to another API. The dotnet core 3.1 middle layer shouldn't be concerned with typing, as the payload will change.

这是传入 API 控制器的对象:

This is the object that is passed into the API Controller:

    public class GitHubAction
    {
        [JsonProperty("Title")]
        public string Title { get; set; }

        [JsonProperty("Enabled")]
        [JsonConverter(typeof(BooleanParseStringConverter))]
        public bool Enabled { get; set; }

        [JsonProperty("Action")]
        [JsonConverter(typeof(ExpandoObjectConverter))]
        public dynamic Action { get; set; }
    }

这是 dynamic 对象在 VSCode 中的样子:

Here is a picture of that dynamic object looks like in VSCode:

当我使用 JsonConvert.SerializeObject(x.Action); 字符串结果没有被正确转换，而是序列化为 ValueKind:"{"ValueKind":1}".

When I use JsonConvert.SerializeObject(x.Action); the string result isn't being properly converted, but instead serializes to ValueKind: "{"ValueKind":1}".

我想要的是作为 JSON 字符串的 action 对象值，它应该看起来像 "{"createRepository":{"onboarding":{"service":{"organization":"foo","repositoryName":"foo-2-service","description":"测试服务."}}}}"

What I want to get is the action object value as a JSON string, which should look like "{"createRepository":{"onboarding":{"service":{"organization":"foo","repositoryName":"foo-2-service","description":"A test service."}}}}"

有没有简单的序列化动态对象的解决方案?

Is there a simple solution for serializing a dynamic object?

推荐答案

我遇到了同样的问题，我是这样解决的

I had the same problem and I fixed it this way

using System.Text.Json;

string serializedObject = JsonSerializer.Serialize(x.Action); //Instead of use JsonConvert.SerializeObject(x.Action);

你必须使用 System.Text.Json 而不是 Newtonsoft.Json.

Instead of Newtonsoft.Json you have to use System.Text.Json.

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