R根据时间间隔通过线性增加估算NA [英] R Impute NA's by Linear Increase Depending on Time Interval
本文介绍了R根据时间间隔通过线性增加估算NA的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
问题
PROBLEM
我需要将数据归因于重复测量研究的NA 。关于此特定结果,我需要从最近观测值开始的每个 +52 周间隔内,以最后观测到的非NA值 +1 估算NA。
I neeed to impute the NA's in my data frame that comes from a repeated measures study. On this particular outcome, I need to impute the NA's with the last observed non-NA value +1 by each +52 week interval starting from the last observed value.
示例
EXAMPLE
带有目标的示例数据框
df <- data.frame(
subject = rep(1:3, each = 12),
week = rep(c(8, 10, 12, 16, 20, 26, 32, 44, 52, 64, 78, 104),3),
value = c(112, 97, 130, 104, NA, NA, NA, NA, NA, NA, NA, NA,
89, 86, 94, 96, 88,107, 110, 102, 107, NA, NA, NA,
107, 110, 102, 130, 104, 88, 82, 79, 92, 106, NA, NA),
goal = c(112, 97, 130, 104, 104, 104, 104, 104, 104, 104, 105, 105,
89, 86, 94, 96, 88,107, 110, 102, 107, 107,107, 108,
107, 110, 102, 130, 104, 88, 82, 79, 92, 106, 106, 106)
)
推荐答案
我将中间列留在使发生的事情更明显,但是您可以使用简单的 select
删除它们。
I left the intermediate columns in to make what's happening more obvious, but you can remove them with a simple select
.
df = df %>%
group_by(subject) %>%
mutate(last_obs_week = max(week[!is.na(value)]),
since_last_week = pmax(0, week - last_obs_week),
inc_52 = since_last_week %/% 52,
result = zoo::na.locf(value) + inc_52
)
all(df$goal == df$result)
# [1] TRUE
print.data.frame(df)
# subject week value goal last_obs_week since_last_week inc_52 result
# 1 1 8 112 112 16 0 0 112
# 2 1 10 97 97 16 0 0 97
# 3 1 12 130 130 16 0 0 130
# 4 1 16 104 104 16 0 0 104
# 5 1 20 NA 104 16 4 0 104
# 6 1 26 NA 104 16 10 0 104
# 7 1 32 NA 104 16 16 0 104
# 8 1 44 NA 104 16 28 0 104
# 9 1 52 NA 104 16 36 0 104
# 10 1 64 NA 104 16 48 0 104
# 11 1 78 NA 105 16 62 1 105
# 12 1 104 NA 105 16 88 1 105
# 13 2 8 89 89 52 0 0 89
# ...
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