Symfony主义实体朋友hasFriend关注者 [英] Symfony Doctrine entity friend hasFriend followers

问题描述

我需要设置关注者，在我的项目中遵循（myFriends）hasFriend逻辑。 odobera一栏的意思是跟随到昵称（id用户）odobera（跟随此用户）。用户（25）跟随用户（37）。

I need to set follower, following (myFriends) hasFriend logic to my project. column "odobera" means "following" to example nick(id user) odobera (following to this user). User (25) is following user(37).

请求表：

 User entity:  

    /**
 * @ORM\OneToMany(targetEntity="TB\RequestsBundle\Entity\Requests", mappedBy="odobera")
 */
protected $followers;    

/**
 * @ORM\OneToMany(targetEntity="TB\RequestsBundle\Entity\Requests", mappedBy="nick")
 */
protected $myFriends; 

public function __construct()
{
    parent::__construct();
     $this->followers = new \Doctrine\Common\Collections\ArrayCollection();
     $this->myFriends = new \Doctrine\Common\Collections\ArrayCollection();
}
/**
 * Get myFriends
 *
 * @return \Doctrine\Common\Collections\Collection 
 */
public function getMyFriends()
{
    return $this->myFriends;
}

/**
 * 
 * @param \TB\UserBundle\Entity\User $user
 * @return bool
 */
public function hasFriend(User $user)
{
    return $this->myFriends->contains($user);
}  

 class Requests
 {

/**
 * @ORM\ManyToOne(targetEntity="TB\UserBundle\Entity\User", inversedBy="myFriends")
 * @ORM\JoinColumn(name="nick", referencedColumnName="id")
 */
protected $nick;    

/**
 * @ORM\ManyToOne(targetEntity="TB\UserBundle\Entity\User",inversedBy="followers")
 * @ORM\JoinColumn(name="odobera", referencedColumnName="id")
 */
protected $odobera;

在控制器中：

       $myFollowers=$user->getMyFriends();

返回：

什么是好：返回1条记录。我实际上只跟随一个人，您可以在这里看到记录的ID是24395

What is good: returns 1 record. I actually follow just one person as you can see here the id of record is 24395

DB请求表：

我不知道getMyFriends函数以该格式返回响应是否良好。请仔细查看它。

I don't know if is good that getMyFriends function returns response in that "format". Please look at it carefully.

然后我从查询和循环中选择了关注者：

Then I have select followers from query and in loop:

{% for follower in followers %}
    and i print data like this (works greate) {{ follower.nick }} 
            or if i want some fields from user entity {{ follower.nick.rank }} 
 {% endfor %}

但问题出在这里：

 {% if (app.user.hasFriend(follower.nick)) %} 

返回false，为什么？当我使用dump：P检入控制器时，我跟随该用户。

That returns false, why? I follow this user as I checked in controller with dump :P Few lines over.

推荐答案

问题似乎是您在比较两个不同类型的变量。

The problem seems to be that you are comparing two different type variable.

执行此操作时： {％if（app.user.hasFriend（follower.nick））％} 会调用以下函数：

When you do this: {% if (app.user.hasFriend(follower.nick)) %} the following function is called:

/**
 * 
 * @param \TB\UserBundle\Entity\User $user
 * @return bool
 */
public function hasFriend(User $user)
{
    return $this->myFriends->contains($user);
}

此函数被调用，以个用户键入 $ user 变量，然后在 contains（）函数> $ this-> myFriends 。

$ this-> myFriends 是 ArrayCollection 的请求（与 User 的类型不同），以及关于 contains（）：

This function is called, taking a User type $user variable and you then use the contains() function on $this->myFriends.
$this->myFriends is an ArrayCollection of Requests (so different type than User) and from the doctrine documentation about contains():

两个元素的比较严格，这意味着不仅
的值，但类型也必须匹配。

The comparison of two elements is strict, that means not only the value but also the type must match.

http://www.doctrine-project.org/api/common/2.1/class-Doctrine.Common。 Collections.ArrayCollection.html

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