TypeError：'函数'对象不可迭代'Python 3 [英] TypeError: 'function' object is not iterable' Python 3

问题描述

我正在尝试编写一个程序，该程序将从网络上打开一个由10,000个单词组成的文本文件，然后清理该文件以消除无用的单词，例如 aa。我最终希望使用这些单词来做其他事情，因此我想将非无意义单词添加到新列表中。每次我尝试运行此命令时，我都会遇到错误代码 TypeError：函数对象不可迭代。

I'm trying to write a program that will open a text file from the web consisting of 10,000 words, then 'clean' the file to get rid of nonsense words, such as 'aa'. I eventually want to use these words to do other things so I want to add the non 'non-sense' words to be put into a new list. Every time i try to run this I run into the error code TypeError: 'function' object is not iterable.

import urllib.request  

def readWordList():  

response = urllib.request.urlopen("http://www.mit.edu/~ecprice/wordlist.10000")
html = response.read()
data = html.decode('utf-8').split()

return data

clean = readWordList() 

def clean(aList):   
    newList = []
    for word in aList: 
        if range(len(word)) >= 2:
            newList.append(word)
    return newList


clean(clean)

推荐答案

下定决心：干净应该是列表还是函数？您从一个列表开始，但是后来用一个函数替换了它，然后告诉函数清理自身。试试这个：

Make up your mind: is clean supposed to be a list or a function? You started as a list, but then replaced that with a function, and then told the function to clean itself. Try this:

dirty_list = readWordList()
def clean(aList):
...

clean(dirty_list)

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