TypeError:'int'对象不可迭代-Python [英] TypeError: 'int' object is not iterable - Python

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本文介绍了TypeError:'int'对象不可迭代-Python的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我遇到以下错误:

  File "/home/ec2-user/test/test_stats.py", line 43, in get_test_ids_for_id
    cursor.execute("""select test_id from test_logs where id = %s """, (id))
  File "/home/ec2-user/.etl/lib/python2.7/site-packages/MySQLdb/cursors.py", line 187, in execute
    query = query % tuple([db.literal(item) for item in args])
TypeError: 'int' object is not iterable

这是我遇到问题的代码部分:

Here's the section of my code I'm having trouble with:

def get_test_ids_for_id(prod_mysql_conn, id):
    cursor = prod_mysql_conn.cursor()
    cursor.execute("""select test_id from test_logs where id = %s """, (id))
    rows = cursor.fetchall()
    test_ids = []
    for row in rows:
      test_ids.append(row[0])
    return test_ids

推荐答案

您需要给cursor.execute一个元组,但只给它一个整数:

You need to give cursor.execute a tuple, but you only gave it one integer:

(id)

添加一个逗号使其成为一个元组:

Add a comma to make that a tuple:

(id,)

完整的行将是:

cursor.execute("""select test_id from test_logs where id = %s """, (id,))

将表达式放在括号中只是将一个表达式分组".是逗号将某些内容变成元组:

Putting an expressione in parentheses just 'groups' that one expression. It is the comma that makes something a tuple:

>>> (42)
42
>>> (42,)
(42,)

任何可迭代的方法都可以做到,因此您也可以使用[...]括号:

Any iterable will do really, so you could also use [...] brackets:

cursor.execute("""select test_id from test_logs where id = %s """, [id])

这篇关于TypeError:'int'对象不可迭代-Python的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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