int对象不可迭代？ [英] int object is not iterable?

问题描述

inp = int(input("Enter a number:"))

for i in inp:
    n = n + i;
    print (n)

...抛出错误： 'int'对象不可迭代

我想通过添加每个数字找出总数，例如110. 1 + 1 + 0 = 2.我该怎么做？

I wanted to find out the total by adding each digit, for eg, 110. 1 + 1 + 0 = 2. How do I do that?

谢谢

推荐答案

首先，失去对 int 的荒谬的召唤 - 这会让你更远从你想要的东西，所以，什么曾经拥有你把它在？！更改：

First, lose that absurd call to int -- which is taking you farther from what you want, so, what ever possessed you to put it in?! Change:

inp = int(input("Enter a number:"))

更简单

inp = input("Enter a number:")

以便 inp 是一串数字，你确实可以逐位循环。

so that inp is a string of digits and you can indeed loop over it, digit by digit.

接下来，将一些初始值赋给 n - 当你现在编码代码时，你会得到一个 NameError ，因为你从来没有初始化它。大概你希望 n = 0 在之前循环。

Next, assign some initial value to n -- as you code stands right now, you'll get a NameError since you never initialize it. Presumably you want n = 0 before the for loop.

接下来，再次考虑字符和整数之间的差异。你现在有：

Next, consider the difference between a character and an integer again. You now have:

n = n + i;

除了完全荒谬（但无害）的分号外，还试图将字符加起来我对整数 n - 这不起作用！所以，这个变成

which, besides the utterly absurd (but innocuous) semicolon, is trying to sum the character i to the integer n -- that won't work! So, this becomes

n = n + int(i)

将字符'7'转换为整数 7 ，等等。

to turn character '7' into integer 7, and so forth.

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