查找具有任何扩展名的特定名称的文件 [英] Finding a file with a specific name with any extension
本文介绍了查找具有任何扩展名的特定名称的文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
请注意,我要更改隔离专区号.
<?php
$compartment = "1";
/* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/
if (file_exists($compartment.$extension)) {
echo "$compartment.$extension exists!
} else {
echo "No file name exists that is called $compartment. Regardless of extension."
}
?>
<?php
$compartment = "2";
/* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/
if (file_exists($$compartment.$extension)) {
echo "$compartment.$extension exists!
} else {
echo "No file name exists that is called $compartment. Regardless of extension."
}
?>
谢谢!
推荐答案
$compartment = "2";
$files = glob("/path/to/files/$compartment.*"); // Will find 2.txt, 2.php, 2.gif
// Process through each file in the list
// and output its extension
if (count($files) > 0)
foreach ($files as $file)
{
$info = pathinfo($file);
echo "File found: extension ".$info["extension"]."<br>";
}
else
echo "No file name exists called $compartment. Regardless of extension."
顺便说一句,您在上面所做的就是哭一个循环.不要重复您的代码块,而是将其中一个包装为:
by the way, what you are doing above is crying for a loop. Don' repeat your code blocks, but wrap one of them into this:
$compartments = array(1, 3, 6, 9); // or whichever compartments
// you wish to run through
foreach ($compartments as $compartment)
{
..... insert code here .......
}
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