如何获得Python中的默认文件权限? [英] How can I get the default file permissions in Python?

问题描述

我正在编写一个Python脚本，在该脚本中，我将输出写入一个临时文件，然后在完成并关闭该文件后将其移至其最终目的地.脚本完成后，我希望输出文件具有与通常通过open(filename,"w")创建的文件相同的权限.照原样，该文件将具有tempfile模块用于临时文件的限制性权限集.

I am writing a Python script in which I write output to a temporary file and then move that file to its final destination once it is finished and closed. When the script finishes, I want the output file to have the same permissions as if it had been created normally through open(filename,"w"). As it is, the file will have the restrictive set of permissions used by the tempfile module for temp files.

如果我在原地创建了输出文件，是否可以通过某种方式弄清楚输出文件的默认"文件权限是什么，以便在移动之前将其应用于临时文件?

Is there a way for me to figure out what the "default" file permissions for the output file would be if I created it in place, so that I can apply them to the temp file before moving it?

推荐答案

出于记录，我遇到了类似的问题，这是我使用的代码:

For the record, I had a similar issue, here is the code I have used:

import os
from tempfile import NamedTemporaryFile

def UmaskNamedTemporaryFile(*args, **kargs):
    fdesc = NamedTemporaryFile(*args, **kargs)
    # we need to set umask to get its current value. As noted
    # by Florian Brucker (comment), this is a potential security
    # issue, as it affects all the threads. Considering that it is
    # less a problem to create a file with permissions 000 than 666,
    # we use 666 as the umask temporary value.
    umask = os.umask(0o666)
    os.umask(umask)
    os.chmod(fdesc.name, 0o666 & ~umask)
    return fdesc

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