如何使用python将对数概率转换为0到1之间的简单概率 [英] How to convert log probability into simple probability between 0 and 1 values using python

问题描述

我正在使用高斯混合模型进行说话人识别.我使用此代码来预测每个语音剪辑的说话者.

I am using Gaussian mixture model for speaker identification. I use this code to predict the speaker for each voice clip.

for path in file_paths:   
    path = path.strip()   
    print (path)
    sr,audio = read(source + path)
    vector   = extract_features(audio,sr)
    #print(vector)
    log_likelihood = np.zeros(len(models))
    #print(len(log_likelihood))

    for i in range(len(models)):
        gmm1   = models[i]  #checking with each model one by one
        #print(gmm1)
        scores = np.array(gmm1.score(vector)) 
        #print(scores)
        #print(len(scores))
        log_likelihood[i] = scores.sum()
        print(log_likelihood)
        winner = np.argmax(log_likelihood)
        #print(winner)
    print ("\tdetected as - ", speakers[winner])

它给了我这样的输出:

[ 311.79769716    0.            0.            0.            0.        ]
[  311.79769716 -5692.56559902     0.             0.             0.        ]
[  311.79769716 -5692.56559902 -6170.21460788     0.             0.        ]
[  311.79769716 -5692.56559902 -6170.21460788 -6736.73192695     0.        ]
[  311.79769716 -5692.56559902 -6170.21460788 -6736.73192695 -6753.00196447]
    detected as -  bart

这里的得分功能为我提供了每个说话者的对数概率.现在，我想确定阈值，为此，我需要将这些对数概率值转换为简单概率值(0到1之间).我怎样才能做到这一点?我正在使用python软件.

Here score function gives me the log probability for each speaker. Now i want to decide threshold value, for that i need these log probability value into simple probability value (between 0 to 1). How can i do that? I am using python software.

推荐答案

您必须采用指数(对数是幂的倒数: e ^{log( p)} = p ，其中p是概率.

You have to take exponent (np.exp()) of the log probabilities to get the actual probabilities back. It's because logarithm is the inverse of exponentiation: e^log(p) = p, where p are the probabilities.

下面是一个示例:

# some input array
In [9]: a
Out[9]: array([1, 2, 3, 4, 5, 6, 7, 8, 9])

# converting to probabilities using "softmax"
In [10]: probs = np.exp(a) / (np.exp(a)).sum()

# sanity check
In [11]: probs.sum()
Out[11]: 1.0

# obtaining log probabilities
In [12]: log_probs = np.log(probs)

In [13]: log_probs
Out[13]: 
array([-8.45855173, -7.45855173, -6.45855173, -5.45855173, -4.45855173,
       -3.45855173, -2.45855173, -1.45855173, -0.45855173])

# In most cases, it won't sum to 1.0
In [14]: log_probs.sum()
Out[14]: -40.126965551706405

# get the probabilities back
In [15]: probabilities = np.exp(log_probs)

In [16]: probabilities.sum()   # check passed
Out[16]: 1.0

In [17]: probabilities
Out[17]: 
array([  2.12078996e-04,   5.76490482e-04,   1.56706360e-03,
         4.25972051e-03,   1.15791209e-02,   3.14753138e-02,
         8.55587737e-02,   2.32572860e-01,   6.32198578e-01])

这篇关于如何使用python将对数概率转换为0到1之间的简单概率的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！