通过接口获取结构的价值 [英] Get value of struct with interfaces
问题描述
我正在尝试解析此请愿书( https: //www.binance.com/api/v1/depth?symbol=MDABTC&limit=500 )
I'm trying to parse this petition (https://www.binance.com/api/v1/depth?symbol=MDABTC&limit=500)
我在为它创建结构时遇到了很多问题,所以我使用了自动化工具,这就是我的结构的样子:
I was having tons of problems to create an struct for it, so I used an automated tool, this is what my struct looks like:
type orderBook struct {
Bids [][]interface{} `json:"Bids"`
Asks [][]interface{} `json:"Asks"`
}
我通过执行以下操作来恢复并解析请愿书:
I recover and parse the petition by doing:
url := "https://www.binance.com/api/v1/depth?symbol=MDABTC&limit=500"
resp, err := http.Get(url)
if err != nil {
panic(err)
}
defer resp.Body.Close()
body, err := ioutil.ReadAll(resp.Body)
if err != nil {
panic(err)
}else{
book := orderBook{}
if err := json.Unmarshal(body, &book); err != nil {
panic(err)
}
但是每当我尝试对该结构进行操作时,就像:
But whenever I try to make an operation with the struct, like:
v := book.Asks[i][0] * book.Asks[i][1]
我得到一个错误:
无效操作:book.Asks [i] [0] * book.Asks [i] [1](运算符*不 在接口上定义)
invalid operation: book.Asks[i][0] * book.Asks[i][1] (operator * not defined on interface)
我如何定义它?我是否需要为bids/asks
创建一个结构,如果是的话,那会是什么样?
How do I define it? Do I need to create an struct for bids/asks
, if so, how would that look like?
对不起,如果这看起来很简单,我就开始学习go.
Sorry if this seems basic, I just started learning go.
推荐答案
在Golang中规范
对于接口类型为T且类型为T的表达式x,主要 表达
For an expression x of interface type and a type T, the primary expression
x.(T)
断言x不是nil,并且存储在x中的值是T类型. x.(T)称为类型断言.
asserts that x is not nil and that the value stored in x is of type T. The notation x.(T) is called a type assertion.
要获取字符串类型的基础值,您需要从接口键入assert到字符串.
Fetching an underlying value of string type you need to type assert to string from interface.
books.Asks[0][0].(string)
要对其执行算术运算,您需要将字符串转换为float64以考虑十进制值
For performing an arithmetic operation on same you needs to convert string into float64 to take into account decimal values
v := strconv.ParseFloat(books.Asks[0][0].(string), 64) * strconv.ParseFloat(books.Asks[0][1].(string), 64)
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